Why would you expect sodium (Na) to react strongly with chlorine (Cl)?

2 answers:

5 0

3. is the answer, <span>Sodium needs to lose one electron, and chlorine needs to gain one electron. This is because Sodium's row always wants to give away an electron, while Chlorine's row wants to gain an electron.</span>

ASHA 777 [7]2 years ago

5 0

Answer: The correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".

Explanation :

The electronic configuration of sodium (Na) is $1s^2\ 2s^2\ 2p^6\ 3s^1$ . It has only one vacant electron.

While the electronic configuration of chlorine is $1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^5$ . It has seven valance electrons.

When Na reacts with Cl, Na will lose one electron and this lost electron gets transferred to chlorine. This forms a strong ionic bond.

So, the correct option is (3) " Sodium needs to lose one electron, and chlorine needs to gain one electron ".

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Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

$I = I_{D} - I_{H}$ (1)

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$I_{D}$ - Moment of inertia of the Disk.

$I_{H}$ - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

$I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)$ (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ( $m$ ):