Explanation:
A nucleus that absorbs 11.45δ is less shielded than a nucleus that absorbs at 4.13δ.
the nucleus that absorbs at 11.45δ requires weaker applied field strength to come into resonance than the nucleus that absorbs at 4.13δ.
We are given that the system “releases” heat of 2,500 J,
and that it “does work on the surroundings” by 7,655 J.
The highlighted words releases and does work on the surroundings
all refers to that it is the system itself which expends energy to do those
things. Therefore the action of releasing heat and doing work has both magnitudes
of negative value. Therefore:
heat released = - 2, 500 J
work done = - 7, 655 J
Which means that the total internal energy change of the
system is:
change in internal energy = heat released + work
<span>change in internal energy = - 2, 500 J + - 7, 655 J</span>
<span>change in internal energy = -10,155 J</span>
Answer:
3. increases with an increase in temperature.
Explanation:
The air more water vapor at higher temperatures because at higher temperatures the air expands and the inter-molecular space increases so the room for water molecules increases.
Warm air keeps the water molecules warm and prevents them from condensing.
The air can hold the moisture only upto its saturation quantity after which the precipitation occurs in the form of rain, snow, hail, sleet etc.
Vertical:
(20 m/s) sin(25º) ≈ 8.45 m/s
Horizontal:
(20 m/s) cos(25º) ≈ 18.1 m/s
