How do fish breathe

A physical property of halite (table salt) is its _____.

nexus9112 [7]

Taste: salty
color: varies. ex: white, clear, purple, yellow, etc.
status: mineral

4 0

3 years ago

Two marbles, one twice as heavy as the other, are dropped to the ground from the roof of a building. Just before hitting the gro

Andreyy89

Answer:

B. twice as much kinetic energy

Explanation:

Lets take the mass of the first marble =2 m

the mass of the second marble = m

We know that velocity of particle does not depends on their mass that is the velocity of both mass will be same after dropping from the roof.

We know that kinetic energy of a mass is given as

$KE=\dfrac{1}{2}Mv^2$

Kinetic energy for heavier mass

$KE=\dfrac{1}{2}\times 2m\times V^2$

Kinetic energy for light mass

$KE'=\dfrac{1}{2}\times m\times V^2$

KE=2 KE '

Form above two equation we can say that ,the kinetic energy for the heavier mass is twice the lighter mass.

Therefore the answer will be B.

7 0

3 years ago

THIS IS MY EXAM HURRY PLS

tangare [24]

Answer:

elements in the same column have the same number of neutrons. elements with similar mass are placed in the same column.

5 0

2 years ago

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19. After a snowstorm, you put on your frictionless skis and tie a rope to the back of your friend’s truck. Your total mass is 7

Kisachek [45]

Explanation:

It is given that,

Total mass is 70 kg

The truck exerts a constant force of 20 N.

Then the net force is given by :

F = ma

a is acceleration of rider

$a=\dfrac{F}{m}\\\\a=\dfrac{20}{70}\\\\a=\dfrac{2}{7}\ m/s^2$

Initial velocity of rider is 0. So, using equation of kinematics to find the final velocity as :

$v=u+at\\\\v=at\\\\v=\dfrac{2}{7}\times 15\\\\v=4.28\ m/s$

Since, 1 m/s = 2.23 mph

4.28 m/s = 9.57 mph

So, the speed of the rider is 4.28 m/s or 9.57 mph.

5 0

2 years ago

A 120 kg tackler moving at 3.0 m/s meets head-on (and tackles) a 91 kg halfback moving at 7.5 m/s. What will be their mutual vel

Vesna [10]

Explanation:

It is given that,

Mass of the tackler, m₁ = 120 kg

Velocity of tackler, u₁ = 3 m/s

Mass, m₂ = 91 kg

Velocity, u₂ = -7.5 m/s

We need to find the mutual velocity immediately the collision. It is the case of inelastic collision such that,

$v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}$

$v=\dfrac{120\ kg\times 3\ m/s+91\ kg\times (-7.5\ m/s)}{120\ kg+91\ kg}$

v = -1.5 m/s

Hence, their mutual velocity after the collision is 1.5 m/s and it is moving in the same direction as the halfback was moving initially. Hence, this is the required solution.

3 0

3 years ago