Answer:
A. 11.5 m
Explanation:
Given,
The initial velocity of the soda cap, u = 15 m/s
The soda bottle cap is projected vertically upwards,
Hence, the angle formed with the ground, Ф = 90°
The maximum height of the projectile is given by the formula,
Substituting the given values in the above equation
= 11.5 m
Hence, the maximum height of the cap is h = 11.5 m
Complete Question:
A 10 kg block is pulled across a horizontal surface by a rope that is oriented at 60° relative to the horizontal surface.
The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by the tension in the rope if the block when the block is 5 m away from its starting point? The coefficient of kinetic friction between the block and the floor is 0.2 and you may assume that the block starting at rest.
Answer:
Power = 54.07 W
Explanation:
Mass of the block = 10 kg
Angle made with the horizontal, θ = 60°
Distance covered, d = 5 m
Tension in the rope, T = 40 N
Coefficient of kinetic friction,
Let the Normal reaction = N
The weight of the block acting downwards = mg
The vertical resolution of the 40 N force,
Power,