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Anuta_ua [19.1K]
1 year ago
10

How many liters are equal to 8 megaliters (ML)?

Chemistry
1 answer:
Reika [66]1 year ago
7 0

Answer:

8000000 litres

Explanation:

General formula,

→ 1 megaliter = 1000000 litres

Then 8 megaliters will be,

→ 8 × 1000000

→ [ 8000000 litres ]

Hence, the solution is 8000000 L.

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How many milliliters of a 0.1000 M NaOH solution would be needed to neutralize a 1.0000-g sample of potassium hydrogen phthalate
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Answer: 2) 2HCl(sq) + CaCO3(s) CaCl2(sq) + CO2(g) + H2O (l) No of moles of CaCO3 = amount of the CaCO3 (g)/mw of CaCO3 (g/mole)= 0.8085 g/100 g/mole = 0.008085

Explanation:

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2 years ago
What is the oxidation number for iodine in Mg(IO3)2 ?
navik [9.2K]
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as 
   Mg(IO3)2
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As we know that
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7 0
2 years ago
Read 2 more answers
A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give
8_murik_8 [283]

<u>Answer:</u> The molality of potassium hydroxide solution is 0.608 m

<u>Explanation:</u>

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

Mass of solvent = Mass of solution - Mass of solute (KOH)

Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}

Where,

m_{solute} = Given mass of solute (KOH) = 3.301 g

M_{solute} = Molar mass of solute (KOH) = 56.1 g/mol

W_{solvent} = Mass of solvent = 96.699 g

Putting values in above equation, we get:

\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m

Hence, the molality of potassium hydroxide solution is 0.608 m

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A.) is the answer =)
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What type of change is this picture showing?
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Answer: physical

Explanation: freezing and melting are physical changes.

8 0
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