Question

Two people decided to race. One of the cars is 10 meters north of the start line 5 seconds into the race. After 15 seconds, the car is 25 meters north of the start line. Calculate the average velocity of the car.

Answer 1

Answer:

The average velocity of the car is 1.5 m/s

Step-by-step explanation:

The given parameters are;

The displacement of one of the cars north of the start after 5 seconds = 10 meters

The displacement of the car north of the start after 15 seconds = 25 meters

The average velocity of the cars $\overline v$ is given as follows;

$\overline v = \dfrac{\Delta x}{\Delta t}$

Where;

Δx = The change in the displacement of the car = 25 m - 10 m = 15 m

Δt = The corresponding amount of the change in time 15 s - 5 s = 10 s

By substituting the known values of Δx and Δt in the equation for the average velocity of the car, $\overline v$, we have;

$\overline v = \dfrac{15 \ m}{10 \ s} = 1.5 \ m/s$

∴ The average velocity of the car, $\overline v$ = 1.5 m/s