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gizmo_the_mogwai [7]
3 years ago
9

The measurement of an exoplanet's radius is measured in units compared to ________.

Physics
2 answers:
slamgirl [31]3 years ago
6 0
Planet Earth's radius
sesenic [268]3 years ago
4 0
The eaths radius is the correct answer, if you need proof look at nasa's website 

You might be interested in
g ) (62.44 pts.) Explain why a maximum or a minimum of occurs exactly when an inflection point occurs for
Ivan

Answer:

we approach a maximum or minimum the values ​​of the ordinate are closer and closer and when passing this point the values ​​change their trend

Explanation:

The reason for this process occurs because as we approach a maximum or minimum the values ​​of the ordinate are closer and closer and when passing this point the values ​​change their trend if they were rising, they begin to fall and if they were falling they begin to rise. Therefore the maximum point is a point of inflection of the curve since its trend changes.

Another way of looking at this process is that mathematically the point where there is a maximum or a minimum corresponds to the point where the first derivative is equal to zero, this is the slope of the line is horizontal, so the points before after correspond to values ​​with slope of different sign.

4 0
3 years ago
How do I solve this problem
PilotLPTM [1.2K]

Answer:

it is light

Explanation:

the arrow that says light is on the glass it must be near from tungsten

5 0
3 years ago
Based on the bond energies given for each of the following which is the most stable? O=O 498 kJ/mol N≡N 946 kJ/mol C=C 614 kJ/mo
slamgirl [31]

Answer:

N≡N bond

Explanation:

Bond energy (bond enthalpy) is a measure of the bond strength in the bond. It is defined as average value of bond dissociation energies in the gas-phase for all the bonds having same type with in same chemical species.

<u>The greater the bond energy, the greater is the amount of energy required to break the bond, the more stable is the bond.</u>

Thus, among the following bonds:

O=O 498 kJ/mol

N≡N 946 kJ/mol

C=C 614 kJ/mol

C=O 745 kJ/mol

C≡C 839 kJ/mol

<u>The greatest bond energy is of N≡N 946 kJ/mol and thats why it is the most stable.</u>

7 0
3 years ago
A non uniform rod has mass
Doss [256]

Answer:

r_{cm} = L/3

Explanation:

Mass: M, Length: L.

\sigma (x) = b(L-x)

The formula that gives center of mass is

\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2 + ...}{m_1 + m_2 + ...} = \frac{\Sigma m_i \vec{r}_i}{\Sigma m_i}

In the case of a non-uniform mass density, this formula converts to

\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx }

where the denominator is the total mass and the nominator is the mass times position of each point on the rod.

We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:

\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx } = \frac{\int\limits^L_0 {xb(L-x)} \, dx }{\int\limits^L_0 {b(L-x)} \, dx } = \frac{b\int\limits^L_0{(xL - x^2)} \, dx }{b\int\limits^L_0 {(L-x)} \, dx } = \frac{\frac{x^2L}{2} - \frac{x^3}{3}}{Lx - \frac{x^2}{2}}\left \{ {{x=L} \atop {x=0}} \right.

Here x's are cancelled. Otherwise, the denominator would be zero.

r_{cm} = \frac{\frac{xL}{2}-\frac{x^2}{3}}{L-\frac{x}{2}}\left \{ {{x=L} \atop {x=0}} \right. = \frac{\frac{L^2}{2}-\frac{L^2}{3}}{L-\frac{L}{2}} = \frac{\frac{L^2}{6}}{\frac{L}{2}} = \frac{L}{3}

8 0
3 years ago
The metal with the highest melting temperature is tungsten which melts at around 3400 K. What is the wavelength of the peak of t
alekssr [168]

Explanation:

It is given that, the metal with the highest melting temperature is tungsten which melts at around 3400 K, T = 3400 K

We need to find the wavelength of the peak of the black body distribution for this temperature. It can be calculated using Wein's displacement law as :

\lambda\times T=k

k is the constant, k=2.89\times 10^{-3}\ m.k

\lambda=\dfrac{k}{T}

\lambda=\dfrac{2.89\times 10^{-3}\ m.k}{3400\ k}

\lambda=8.5\times 10^{-7}\ m

or

\lambda=850\ nm

The wavelength of infrared is from 700 nm to 1 mm. So, the lies in infrared region of the spectrum. Hence, this is the required solution.

7 0
4 years ago
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