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frozen [14]
3 years ago
6

A pressure cooker contains 5.68 liters of air at a temperature of 394 K. If the absolute pressure of the air in the pressure coo

ker is 205 pascals, how many moles of air are in the cooker? The cooker contains _______ moles of air. 1 SEE ANSWER
Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

Explanation:

We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )

Let it be V₂

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

\frac{2\times 10^5\times 5.68}{394} =\frac{10^5\times V_2}{273}

V₂ = 7.87 litres

22.4 litres of any gas is equivalent to 1 mole

7.87 litres of air will be equivalent to

7.87 / 22.4 moles

= .35 moles .

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The answer is D, apart
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Given the thermochemical equations below, What is the standard heat of formation of CuO(s)? 2 Cu2O(s) + O2(g) ---&gt; 4 CuO(s) ∆
OlgaM077 [116]

-130KJ is the standard heat of formation of CuO.

Explanation:

The standard heat of formation or enthalpy change can be calculated by using the formula:

standard heat of formation of reaction = standard enthalpy of formation of product - sum of enthalpy of product formation

Data given:

Cu2O(s) ---> CuO(s) + Cu(s) ∆H° = 11.3 kJ

2 Cu2O(s) + O2(g) ---> 4 CuO(s) ∆H° = -287.9 kJ

CuO + Cu ⇒ Cu2O (-11.3 KJ)      ( Formation of Cu2O)

When 1 mole Cu20 undergoes combustion 1/2 moles of oxygen is consumed.

Cu20 + 1/2 02 ⇒ 2CuO (I/2 of 238.7 KJ) or 119.35 KJ

So standard heat of formation of  formation of Cu0 as:

Cu + 1/2 02 ⇒ CuO

putting the values in the equation

ΔHf = ΔH1 + ΔH2     (ΔH1 + ΔH2  enthalapy of reactants)

heat of formation = -11.3 + (-119.35)

                            = - 130.65kJ

-130.65 KJ is the heat of formation of CuO in the given reaction.

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3 years ago
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Spindle fibers break down during what phase?
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Answer: Prophase.
In prophase, chromosomes condense and become visible. Spindle fibers emerge from the centrosomes.
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If a chemical reaction catalyzed by an enzyme is being carried out, and there is a sudden, drastic decrease in temperature, what
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If a chemical reaction catalyzed by an enzyme is being carried out, and there is a sudden, drastic decrease in temperature, the thing that will most likely to happen next is going to be the :

“enzyme activity will decrease, and the reaction will proceed very slowly, or possibly not at all.“

Explanation:

This compliance is required to how enzymes bind to other molecules and cause chemical reactions to occur on those molecules. Lowering the temperature reduces the motion of molecules and atoms, expecting this compliance is reduced or lost. As the temperature decreases, so do enzyme activity. While higher temperatures do increase the activity of enzymes and the rate of reactions,

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How many liters of hydrogen gas are formed from the complete reaction of 1.03 mol of C? Assume that the hydrogen gas is collecte
aliina [53]

Answer:

27 liters of hydrogen gas will be formed

Explanation:

Step 1: Data given

Number of moles C = 1.03 moles

Pressure H2 = 1.0 atm

Temperature = 319 K

Step 2: The balanced equation

C +H20 → CO + H2

Step 3: Calculate moles H2

For 1 mol C we need 1 mol H2O to produce 1 mol CO an 1 mol H2

For 1.03 moles C we'll have 1.03 moles H2

Step 4: Calculate volume H2

p*V = n*R*T

⇒with p = the pressure of the H2 gas = 1.0 atm

⇒with V = the volume of H2 gas = TO BE DETERMINED

⇒with n = the number of moles H2 gas = 1.03 moles

⇒with R = the gas constant = 0.08206 L*Atm/mol*K

⇒with T = the temperature = 319 K

V = (n*R*T)/p

V = (1.03 * 0.08206 *319) / 1

V = 27 L

27 liters of hydrogen gas will be formed

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3 years ago
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