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frozen [14]
3 years ago
6

A pressure cooker contains 5.68 liters of air at a temperature of 394 K. If the absolute pressure of the air in the pressure coo

ker is 205 pascals, how many moles of air are in the cooker? The cooker contains _______ moles of air. 1 SEE ANSWER
Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

Explanation:

We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )

Let it be V₂

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

\frac{2\times 10^5\times 5.68}{394} =\frac{10^5\times V_2}{273}

V₂ = 7.87 litres

22.4 litres of any gas is equivalent to 1 mole

7.87 litres of air will be equivalent to

7.87 / 22.4 moles

= .35 moles .

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Suppose a gas starts with a volume of 4.52L, temperature of 23 C, and pressure of 102,00 Pa. If the volume changes to 4.83L and
ivanzaharov [21]

Answer:

The answer to your question is     P2 = 84.16 kPa

Explanation:

Data

Volume 1 = V1 = 4.52 L            Volume 2 = V2 = 4.83 l

Pressure 1 = P1 = 102 kPa        Pressure 2 = P2 = ?

Temperature 1 = T1 = 23°C      Temperature 2 = T2 = -12°C

Process

1.- Convert the temperature to °K

Temperature 1 = 23 + 273 = 296°K

Temperature 2 = -12 + 273 = 261°K

2.- Use the Combined Gas law to solve this problem

                  P1V1/T1 = P2V2/T2

-Solve for P2

                  P2 = P1V1T2 / T1V2

-Substitution

                  P2 = (102)(4.52)(261) / (296)(4.83)

-Simplification

                  P2 = 120331.44 / 1429.68

-Result

                  P2 = 84.16 kPa

8 0
3 years ago
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