Question

How many moles of hydrochloric acid are present in 62.2 mL of 4.54 M HCl solution

Answer 1

Moles of HCl = 0.282

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = number of moles of solute

V = Volume of solution

The volume of HCl=62.2 ml=0.0622 L

The molarity of HCl = 4.54 M

Then moles of HCl :

$\tt n=M\times V\\\\n=4.54\times 0.0622\\\\n=0.282~moles$