Question

As a young boy swings a yo-yo parallel to the ground and above his head, the yo-yo has a centripetal acceleration of 250 m/s2 . If the yo-yo’s string is 0.50 m long, what is the yo-yo’s tangential speed?

Answer 1

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

$a_c = \dfrac{v^2}{R}$

Solving for v:

$v = \sqrt{a_c R} = \sqrt{(250\;m/s^2)(0.50\;m)} = 5\sqrt{5}\;m/s \approx 11.18\;m/s$

Answer 2

what he put is correct!!

Explanation: