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Daniel [21]
2 years ago
12

As a young boy swings a yo-yo parallel to the ground and above his head, the yo-yo has a centripetal acceleration of 250 m/s2 .

If the yo-yo’s string is 0.50 m long, what is the yo-yo’s tangential speed?
Physics
2 answers:
Ahat [919]2 years ago
8 0

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

a_c = \dfrac{v^2}{R}

Solving for v:

v = \sqrt{a_c R} =  \sqrt{(250\;m/s^2)(0.50\;m)} = 5\sqrt{5}\;m/s \approx 11.18\;m/s

Lorico [155]2 years ago
4 0

what he put is correct!!

Explanation:

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ivolga24 [154]

Answer:

The acceleration of the wallet is 3\hat{i}+6\hat{j}

Explanation:

Given that,

Radius of purse r= 2.30 m

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We need to calculate the acceleration of the wallet

Using formula of acceleration

a=r\omega^2

Both the purse and wallet have same angular velocity

\omega=\omega'

\sqrt{\dfrac{a}{r}}=\sqrt{\dfrac{a'}{r'}}

\dfrac{a}{r}=\dfrac{a'}{r'}

\dfrac{a'}{a}=\dfrac{r'}{r}

\dfrac{a'}{a}=\dfrac{3.45}{2.30}

\dfrac{a'}{a}=\dfrac{3}{2}

a'=\dfrac{3}{2}\times(2\hat{i}+4.00\hat{j})

a'=3\hat{i}+6\hat{j}

Hence, The acceleration of the wallet is 3\hat{i}+6\hat{j}

4 0
3 years ago
What is the role of the neutral wire
lions [1.4K]

Answer:

The neutral wire is often confused with ground wire, but in reality, they serve two distinct purposes. Neutral wires carry currents back to power source to better control and regulate voltage. Its overall purpose is to serve as a path to return energy.

5 0
2 years ago
Two iron bolts of equal Mass one at a hundred see another at 55 Sierra place in the insulated cylinder assuming the heat capacit
malfutka [58]

Answer:

T_2 = 77.5c

Explanation:

From the question we are told that

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Temp of 2nd bolt T_2=55

Generally the equation showing the relationship between  heat & temperature is given by

  q=cm \triangle T

Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     -(0.45*m* (T_2-100  \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)

     -(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)

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      T_2 = 77.5 \textdegree c

Therefore T_2 = 77.5 \textdegree c is the final temperature inside the container

5 0
2 years ago
sonic is sliding down a frictionless 15m tall hill. He starts at the top with a velocity of 10m/s. At the bottom of the hill he
podryga [215]

Answer:

The maximum speed of sonic at the bottom of the hill is equal to 19.85m/s and the spring constant of the spring is equal to (497.4xmass of sonic) N/m

Energy approach has been used to sole the problem.

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The maximum velocity of sonic is independent of the his mass or the geometry. It is only depends on the vertical distance involved

Explanation:

The step by step solution to the problem can be found in the attachment below. The principle of energy conservation has been applied to solve the problem. This means that if energy disappears in one form it will appear in another.

As in this problem, the potential and kinetic energy at the top of the hill were converted to only kinetic energy at the bottom of the hill. This kinetic energy too got converted into elastic potential energy .

x = compression of the spring = 0.89

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Alex17521 [72]

Answer: Rn :)))) no explanation needed

3 0
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