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Daniel [21]
2 years ago
12

As a young boy swings a yo-yo parallel to the ground and above his head, the yo-yo has a centripetal acceleration of 250 m/s2 .

If the yo-yo’s string is 0.50 m long, what is the yo-yo’s tangential speed?
Physics
2 answers:
Ahat [919]2 years ago
8 0

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

a_c = \dfrac{v^2}{R}

Solving for v:

v = \sqrt{a_c R} =  \sqrt{(250\;m/s^2)(0.50\;m)} = 5\sqrt{5}\;m/s \approx 11.18\;m/s

Lorico [155]2 years ago
4 0

what he put is correct!!

Explanation:

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FrozenT [24]

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2 years ago
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50 μm2. Convert this
Paladinen [302]
1 m = 1 000 000 ym

converted other way we can say that:

1 ym = 10^{-6} m

Now, since we have ym^2 which is ym*ym which means:
1 ym^2 = (10^{-6}) ^2  =  10^{-12} m

we have 1,5 ym^2 which means that answer is:
1.5* 10^{-12} m
8 0
3 years ago
A car radio draws 0.27 A of current in the autos 12-V electrical system. (a) How much electric power does the radio use?
Lostsunrise [7]

Answer:

(a) 3.24 w (b) 44.44 ohm

Explanation:

It is given that car draws 0.27 A current so current I = 0.27 A

The system has a voltage of 12 V

(a) Electrical power = voltage ×current =12\times 0.27=3.24W

(b) The resistance is defined as the ratio of voltage and current

So resistance R=\frac{V}{I}=\frac{12}{0.27}=44.44 ohm

8 0
3 years ago
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what times are the moon phases visible? My science teacher said that the phases of the moon are only visible at sertant times of
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