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Illusion [34]
3 years ago
11

State branches of geography and explain​

Physics
1 answer:
agasfer [191]3 years ago
8 0

Answer:

Geography is divided into two main branches: human geography and physical geography. There are additional branches in geography such as regional geography, cartography, and integrated geography....

hope it helps please follow

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Imma go with A.

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A spring has a spring constant of 80 N/m. How much energy is stored in the spring when it is compressed 0.2 m past its natural l
Paha777 [63]
The energy of a compressed (or stretched) spring is given by

E= \frac{1}{2} k x^{2}

This gives

E= \frac{1}{2}80* 0.2^{2}  =1.6J
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Which scientist proved experimentally that a shadow of the circular object illuminated 18. with coherent light would have a cent
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Your answer is( D) - Arago

8 0
3 years ago
21. An AC generator has an rms output voltage of 274 V at a frequency of 57.0 Hz.
maks197457 [2]

The answers are as follows;

a) the inductive reactance is 322 ohm

b) The maximum voltage is 387.5 V

c) The rms and maximum currents in the inductor are 1.2 A and 0.85 A.

<h3>What is the reactance?</h3>

The reactance is obtained from;

XL = 2πfL

XL = 2 * 3.14 * 57.0 * 0.900

XL = 322 ohm

The maximum voltage is obtained as;

Vo = Vrms * √2

Vo =  274 V * √2

Vo = 387.5 V

Io = Vo/XL

Io =  387.5 V/ 322 ohm

Io = 1.2 A

Irms = 274 V/322 ohm

Irms = 0.85 A

Learn more about inductive reactance:brainly.com/question/17129912

#SPJ1

4 0
2 years ago
Two resistances, R1 and R2, are connected in series across a 12-V battery. The current increases by 0.500 A when R2 is removed,
KATRIN_1 [288]

Answer:

a)   R₁ = 14.1 Ω,   b)  R₂ =  19.9 Ω

Explanation:

For this exercise we must use ohm's law remembering that in a series circuit the equivalent resistance is the sum of the resistances

all resistors connected

           V = i (R₁ + R₂)

with R₁ connected

           V = (i + 0.5) R₁

with R₂ connected

           V = (i + 0.25) R₂

We have a system of three equations with three unknowns for which we can solve it

We substitute the last two equations in the first

           V = i ( \frac{V}{ i+0.5} + \frac{V}{i+0.25} )

           1 = i ( \frac{1}{i+0.5} + \frac{1}{i+0.25} )

           1 = i ( \frac{i+0.5+i+0.25}{(i+0.5) \ ( i+0.25) } ) =  \frac{i^2 + 0.75i}{i^2 + 0.75 i + 0.125}

           i² + 0.75 i + 0.125 = 2i² + 0.75 i

           i² - 0.125 = 0

           i = √0.125

           i = 0.35355 A

with the second equation we look for R1

          R₁ = \frac{V}{i+0.5}

          R₁ = 12 /( 0.35355 +0.5)

          R₁ = 14.1 Ω

with the third equation we look for R2

          R₂ = \frac{V}{i+0.25}

          R₂ =\frac{12}{0.35355+0.25}

          R₂ =  19.9 Ω

3 0
2 years ago
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