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Marina86 [1]
3 years ago
14

Lexi is balancing equations. She is finding one equation to be very difficult to balance. Which explains how to balance the equa

tion ZnSO4 + Li2CO3 → ZnCO3 + Li2SO4?
Chemistry
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

deez

Explanation:

thx

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What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
Alika [10]

Answer:- B: 1.10g H_2 is the right answer.

Solution:- The balanced equation is:

O_2(g)+2H_2(g)\rightarrow 2H_2O(g)

We have been given with 8.75 grams of oxygen and asked to calculate the grams of hydrogen needed to react with given grams of oxygen according to the balanced equation.

From balanced equation, 1 mole of oxygen reacts with 2 moles of hydrogen.

So, let's convert grams of oxygen to moles and multiply it by the mole ratio to calculate the moles of hydrogen that are easily converted to grams on multiplying by it's molar mass.

The complete set up looks as:

8.75g O_2(\frac{1mole}{32g})(\frac{2mole H_2}{1mole O_2})(\frac{2.02g}{1mole})

= 1.10g H_2

Hence, the right option is B: 1.10g H_2 .



7 0
4 years ago
Read 2 more answers
Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
4 years ago
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