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maxonik [38]
3 years ago
11

Two vectors at different angles how can calculate the resultant force?​

Physics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

The diagonal of the parallelogram PBCA is the resultant force R, which forms two scalene triangles with the forces F1 and F2. Since the sum of all the angles within a triangle is 180°, we can write γ function of α and β. The resultant force can also be calculated analytical, using force projections.

Explanation:

Please give thanks to all my answers and please mark as brilliant and please follow me

Ratling [72]3 years ago
6 0

Answer:

In order to calculate the magnitude and direction of a resultant force or to calculate the value of one force component or another, we can use the law of sines and the law of cosines.

...

The forces and angles are as follows:

F1 = 2.91 N, α1 = 0°

F2 = 2.67 N, α2 = 60°

F3 = 2.47 N, α3 = 150°

F4 = 2.23 N, α4 = 270°

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Calculate the force, when a object acelerattes to 30 m/s^2 and have a mass of 40 kg
faust18 [17]

Hello!

Use the <u>second law of Newton:</u>

F = ma

Replacing:

F = 40 kg * 30 m/s^2

Resolving:

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Badri makes the table below to review the factors that affect the electric force between objects. Which change will correct the
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4 years ago
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Calculate the initial (from rest) acceleration of a proton in a 5.00 x 10^6 N/C electric field (such as created by a research Va
julsineya [31]

Answer:

Acceleration of the proton will be equal to 4.79\times 10^{14}m/sec^2

Explanation:

We have given electric field E=5\times 10^6N/C

Mass of proton is equal to m=1.67\times 10^{-27}kg

And charge on proton is equal to e=1.6\times 10^{-19}C

Electrostatic force will be responsible for the motion of proton

Electrostatic force will be equal to F=qE=1.6\times 10^{-19}\times 5\times 10^6=8\times 10^{-13}N

According to newton law force on the proton will be equal to F = ma, here m is mass of proton and a is acceleration

This newton force will be equal to electrostatic force

So 1.67\times 10^{-27}\times a=8\times 10^{-13}

a=4.79\times 10^{14}m/sec^2

So acceleration of the proton will be equal to 4.79\times 10^{14}m/sec^2

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