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maxonik [38]
3 years ago
11

Two vectors at different angles how can calculate the resultant force?​

Physics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

The diagonal of the parallelogram PBCA is the resultant force R, which forms two scalene triangles with the forces F1 and F2. Since the sum of all the angles within a triangle is 180°, we can write γ function of α and β. The resultant force can also be calculated analytical, using force projections.

Explanation:

Please give thanks to all my answers and please mark as brilliant and please follow me

Ratling [72]3 years ago
6 0

Answer:

In order to calculate the magnitude and direction of a resultant force or to calculate the value of one force component or another, we can use the law of sines and the law of cosines.

...

The forces and angles are as follows:

F1 = 2.91 N, α1 = 0°

F2 = 2.67 N, α2 = 60°

F3 = 2.47 N, α3 = 150°

F4 = 2.23 N, α4 = 270°

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Which of the following is an example of the Doppler effect? A water bug on the surface of a pond is producing small ripples in t
noname [10]

Answer:

A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.

Explanation:

In Physics, Doppler effect can be defined as the change in frequency of a wave with respect to an observer in motion and moving relative to the source of the wave.

Simply stated, Doppler effect is the change in wave frequency as a result of the relative motion existing between a wave source and its observer.

The term "Doppler effect" was named after an Austrian mathematician and physicist known as Christian Johann Doppler while studying the starlight in relation to the movement of stars.

<em>The phenomenon of Doppler effects is generally applicable to both sound and light. </em>

An example of the Doppler effect is a police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase. This is so because when a sound object moves towards you, its sound waves frequency increases, thereby causing a higher pitch. However, if the sound object is moving away from the observer, it's sound waves frequency decreases and thus resulting in a lower pitch.

<em>Other fields were the Doppler effects are applied are; astronomy, flow management, vibration measurement, radars, satellite communications etc. </em>

3 0
4 years ago
A generator coil is rotated one quarter of a full revolution, from θ = 0° to θ = 90°,
IgorLugansk [536]

The maximum electromotive force induced in the coil by the generator is 56.45 V.

<h3>Maximum electromotive force induced in the coil</h3>

emf(max) = NAB/t

where;

  • N is number of turns
  • A is area
  • B is magnetic field
  • t is time

Substitute the given parameter and solve for maximum electromotive force induced in the coil.

Area of the loop = 0.0462 m x 0.0462 m = 0.00213 m²

emf(max) = (353 x 0.00213 x 0.991) / (13.2 x 10⁻³)

emf(max) = 56.45 V

Thus, the maximum electromotive force induced in the coil by the generator is 56.45 V.

Learn more about electromotive force here: brainly.com/question/24158806

#SPJ1

6 0
2 years ago
a 2.00 kg friction-less block is attached to an ideal spring with force constant 315 N/m.Initially, the spring is neither stretc
Setler [38]

Answer

given,

mass of block, m = 2 Kg

spring constant, k = 315 N/m

speed of the block, v = 12 m/s

a) Amplitude of the motion

   A = v \sqrt{\dfrac{k}{m}}

   A =\dfrac{12}{\sqrt{\dfrac{315}{2}}}

         A = 0.956 m

b) maximum acceleration of the block

    a_{max}= A \dfrac{k}{m}

    a_{max}= 0.956\times \dfrac{315}{2}

    a_{max}= 150.57\ m/s^2

c) maximum Force

  F_{max} = m a_{max}

  F_{max} = 2\times 150.57

  F_{max} = 301.14\ N

5 0
3 years ago
What force would be needed to make a 10kg bowling ball accelerate down the alleyway with an acceleration of 3m/s2
Anna007 [38]

Answer:

30 N

Explanation:

From Newton's second law:

F = ma

F = (10 kg) (3 m/s²)

F = 30 N

7 0
4 years ago
A car is driving at 85 km/h and the driver spots a stop sign ahead. What coefficient of friction is needed to stop the car at th
almond37 [142]

Answer:

μ = 0.0315

Explanation:

Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)

N = m*g (1)

The friction force is equal to the product of the normal force by the coefficient of friction.

F = μ*N (2)

This way replacing 1 in 2, we have:

F = μ*m*g (2)

Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.

\frac{1}{2} *m*v_{i}^{2}-(F*d)=  \frac{1}{2} *m*v_{f}^{2}

where:

vf = final velocity = 0

vi = initial velocity = 85 [km/h] = 23.61 [m/s]

d = displacement = 900 [m]

F = friction force [N]

The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.

Now replacing:

(1/2)*m*(23.61)^2 = μ*m*g*d

0.5*(23.61)^2 = μ*9,81*900

μ = 0.0315

5 0
3 years ago
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