Answer:
1. Net force = 90 N
2. Acceleration = 9 m/s²
Explanation:
From the question given above, the following data were obtained:
Mass (m) of bag = 10 Kg
Force applied 1 (Fₐ₁) = 45 N
Force applied 2 (Fₐ₂) = 60 N
Force of friction (Fբ) = 15 N
Net force (Fₙ) =?
Acceleration (a) =?
1. Determination of the net force acting on the bag.
We'll begin by calculating the total force applied on the bag.
Force applied 1 (Fₐ₁) = 45 N
Force applied 2 (Fₐ₂) = 60 N
Total force applied = Fₐ₁ + Fₐ₂
Total force applied = 45 + 60
Total force applied = 105 N
Finally, we shall determine the net force acting on the bag. This is illustrated below:
Total force applied = 105 N
Force of friction (Fբ) = 15 N
Net force (Fₙ) =?
Net force (Fₙ) = Total force applied – Force of friction (Fբ)
Net force (Fₙ) = 105 – 15
Net force (Fₙ) = 90 N to the right
2. Determination of the acceleration of the bag.
Mass (m) of bag = 10 Kg
Net force (Fₙ) = 90 N
Acceleration (a) =?
Force (F) = mass (m) × acceleration (a)
90 = 10 × a
Divide both side by 10
a = 90 / 10
a = 9 m/s²
Thus, the acceleration of the bag is 9 m/s² to the right.
