<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
it depends on the gravitational force of attraction of earth and air resistance.
if we are neglecting air resistance, the max.horizontal distance is according to this formulae,
V0/2 * sin (2theta)
where V0 is the initial velocity
theta is the angle with x axis and the projection.
There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>
Dependent variable is time
Explanation:
The dependent variable is the variable that is affected by a change in parameters or the condition. It is usually the effect of some experimental process.
Here, the time at which the ball comes to halt depends on the nature of the surface.
The surface is the independent variable, it more like the cause.
In this experiment different surfaces would be used in order to find the time at which the ball comes to a stop.
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Experiment brainly.com/question/5096428
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All the options are wrong is there another?
Answer:
significant figures are the meaningful digits which are known with certainity . the number of significant figures in a measurement is the number of figures plus one that is uncertain, Begginig with the first non-zero digit e. g 8.00 has three significant figures
Answer:
2.38 mW
Explanation:
Power is work per unit time. Work is the product of force and distance. That means ...

Using the given values of force and velocity, the tadpole's power output is ...
P = (0.028 N)(0.085 m/s) = 0.00238 W = 2.38 mW
The tadpole's power output is about 2.38 mW.