Answer:
B: it allow quick conversation to others
Answer:
1.33 moles CO2
Explanation:
The number you are converting is 58.4 g CO2, so you start with this value. The conversion factor is 44.0 g/mol CO2. In order to cross out the grams, the grams must go on the bottom of the conversion factor.
1 mol CO2
58.4 g CO2 x -------------------------- = 1.33 moles CO2
44.0 grams
The answer has three sig figs.
Answer:
(slow)xy2+z→xy2z (fast) c step1:step2:xy2+z2→xy2z2
Explanation:
Step1: xy2+z2→xy2z2 (slow)
Step2: xy2z2→xy2z+z (fast)
2XY 2 + Z 2 → 2XY 2 Z
Rate= k[xy2][z2]
When the two elementary steps are summed up, the result is equivalent to the stoichiometric equation. Hence, this mechanism is acceptable. The order of both elementary steps is 2, which is ‘≤3’; this also makes this mechanism acceptable. Furthermore, the rate equation aligns with the experimentally determined rate equation, and this also makes this mechanism acceptable. Therefore, since all the three rules have been observed, this mechanism is possible.
In physical science applying a force over a displacement is called work.
In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.
As, Moles is given as,
Moles = Mass / M.mass
Moles = 0.53 g ÷ 283.88 g.mol⁻¹
Moles = 0.00186 moles
Now calculate the number of Molecules present in calculated moles of P₂O₅.
As,
1 Mole of P₂O₅ contains = 6.022 × 10²³ Molecules
So,
0.00186 Moles of P₂O₅ contain = X Molecules
Solving for X,
X = (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol
X = 1.12 × 10²¹ Molecules
Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....
= 1.12 × 10²¹ × 7
= 7.84 × 10²¹ Atoms
Result:
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.
