Answer:
Density of Air = ( - )/(g x h)
Density of Air = 1.27 Kg/
Explanation:
Note: This question is not complete, and lacks its first part in which it contains important data to solve for the density of air. But, I have found the similar question and its data. So. I will be solving the question for the sack of understanding and concept.
Missing part: A weather balloon has an absolute-pressure sensor attached. On the ground the sensor reads = 1.01x Pa. At a height of h = 950 m, the sensor reads =8.92x Pa.
Solution:
Let
be the pressure of the balloon at ground.
be the pressure of the balloon at height h = 950 m
g = acceleration due to gravity,
In order to derive the expression, we need to find the pressure difference:
Pressure difference = ΔP
ΔP = -
As we know that,
Pressure difference = density x acceleration due to gravity x height.
So,
ΔP = - = (Density of Air) x (g) x (h)
We need expression for the density of air, so,
Density of Air = ΔP / (g x h)
Hence, the expression is:
Density of Air = ( - )/(g x h)
Now, we can calculate the density of air as well, by putting the values given above in the data.
= 1.01 x
= 8.92 x
g = 9.8 m/s
h = 950 m
So,
Density of Air = ((1.01 x ) - (8.92 x ) )/ (9.8 x 950)
Density of Air = 1.27 Kg/