The answer is reduction reaction. For every oxidation reaction that takes place, a reduction reaction must also happen, no reduction can occur without oxidation and vice versa. In redox reaction, atoms or ions undergo changes in the electronic structure, involving the transfer of electrons between reactants.
Answer:
sicl - Silty clay loam: 27 to 40 percent clay and less than 20 percent sand. sc - Sandy clay: 35 percent or more clay and 45 percent or more sand. sic - Silty clay: 40 percent or more clay and 40 percent or more silt. c - Clay: 40 percent or more clay, less than 45 percent sand, and less than 40 percent silt.
I hope that helps somewhat, sorry
Answer:
64.0 g/mol.
Explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
<em>∨ ∝ 1/√M.</em>
where, ∨ is the rate of diffusion of the gas.
M is the molar mass of the gas.
<em>∨₁/∨₂ = √(M₂/M₁)</em>
∨₁ is the rate of effusion of the unknown gas.
∨₂ is the rate of effusion of He gas.
M₁ is the molar mass of the unknown gas.
M₂ is the molar mass of He gas (M₂ = 4.0 g/mol).
<em>∨₁/∨₂ = 0.25.</em>
∵ ∨₁/∨₂ = √(M₂/M₁)
∴ (0.25) =√(4.0 g/mol)/(M₁)
<u><em>By squaring the both sides:</em></u>
∴ (0.25)² = (4.0 g/mol)/(M₁)
∴ M₁ = (4.0 g/mol)/(0.25)² = 64.0 g/mol.
Answer:
i think C it's okay beacause of Density
Answer:
The answer to the question is;
The concentration of the Solution #1 in terms of molarity is
0.16704X moles/litre.
Explanation:
Let the concentration of the stock solution be X moles/liter
Therefore, 83.52 ml of the stock solution contains
83.52×(X/1000) moles
Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of
500 ml of solution 1 contains 83.52×(X/1000) moles
Therefore 1000 ml or 1 litre contains 2×83.52×(X/1000) moles = 0.16704X moles/litre
The molarity of solution 1 is 0.16704X moles/litre.