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slamgirl [31]
3 years ago
5

When H2(g) reacts with Cl2(g) to form HCl(g) , 185 kJ of energy are evolved for each mole of H2(g) that reacts. Write a balanced

thermochemical equation for the reaction with an energy term in kJ as part of the equation. Note that the answer box for the energy term is case sensitive. Use the SMALLEST INTEGER coefficients possible and put the energy term (including the units) in the last box on the appropriate side of the equation. If a box is not needed, leave it blank.
Chemistry
1 answer:
Katyanochek1 [597]3 years ago
7 0

Answer:

H₂(g) + Cl₂(g) → 2HCl(g) + 185kJ

Explanation:

In a chemical reaction, enthalpy of reaction ΔH is a thermodynamic constant that gives information if the reaction is exothermic (Produce heat if reacts) or endothermic (Consume heat if reacts).

In the reaction:

H₂(g) + Cl₂(g) → 2HCl(g) ΔH = -185kJ

As ΔH <0, the reaction is exothermic, that means, <em>produce heat</em>, writing a balanced thermochemical equation:

<em>H₂(g) + Cl₂(g) → 2HCl(g) + 185kJ</em>

<em></em>

The enthalpy is as a product beacause an exothermic reaction produces heat.

I hope it helps!

<em></em>

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A team of geologists is surveying on a mountain. They come across a newly formed stream. The stream is flowing at an average rat
zhannawk [14.2K]

Answer:

35 minutes

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The flow rate of the stream is the rate of volume of water with respect to time. It expresses the volume of water flowing per unit time.

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From the given question,

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So that;

time = \frac{volume}{flow rate}

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BASED ON THE INFORMATION BELOW. CALCULATE THE MASS FOR ONE OF THESE ATOMS:
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C = 12 g

O = 16 g

H = 1 g

<h3>Further explanation </h3>

Conservation of mass stated that  

<em>In a closed system, the masses before and after the reaction are the same </em>

we can calculate the mass of each atom in the compound :

O in O₂ :

mass O₂ = 32

mass O = 32 : 2 = 16 g

H in H₂O

mass H₂O = 18

mass 2.H + mass O = 18

mass 2.H + 16 = 18

mass 2.H=2

mass H = 1 g

C in CH₄

mass CH₄ = 16

mass C + mass 4.H = 16

mass C + 4.1=16

mass C = 12 g

or we can use formula :

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\tt =\dfrac{Ar~C}{MW~CO_2}\times mass~CO_2\\\\=\dfrac{12}{44}\times 44=12

7 0
3 years ago
How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?
zhannawk [14.2K]

The heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J. (approx= 3963J).

<h3>What is Sensible heat? </h3><h3 />

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state.

Q= c×m×∆T

<h3>What is Latent heat? </h3><h3 />

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q= m×L

Where,

L is the latent heat

<h3>-10°C to 0 °C</h3><h3 />

C= specific heat capacity of ice= 2.108 J/gK

M= 10 g

ΔT= T(final)– T(initial) = 0 °C – (-10 °C)= 10 °C= 10 K

Sensitive heat Q(1) = 2.108×10×10

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<h3>Heat needed to melt ice</h3><h3 />

The specific heat of melting of ice is 334 J/g, the heat needed to melt 10 grams of ice is

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<h3>0°C to 10 °C</h3><h3 />

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Total heat required= Q1 + Q2 + Q3

Total heat required= 210.8 J + 3,340 J + 418.7 J

= 3969.5J

Thus, the heat needed to melt 10 gram of ice from temperature-10°C to 10°C is 3969.5. Therefore, option B is correct option.

learn more about heat :

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