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3 years ago

Use the model provided to select ALL of the examples of mixtures.

Chemistry

2 answers:

Serggg [28]3 years ago

6 0

Answer:

Explanation:

Ice tea

Salt water

Orange juice

ruslelena [56]3 years ago

3 0

Where is the model? I do know salt water is a mixture though

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The mass of a proton is 1.00728 amu and that of a neutron is 1.00867 amu. what is the binding energy (in j) of a 61co nucleus? (

bazaltina [42]

With the given equations the binding energy is $1.372 *10^{-12} J$ .

<h3>How will you calculate binding energy using the given equations?</h3>

Step 1: The given data is:

The proton's mass 1.00728 amu

The neutron's mass 1.00867 amu

The mass of a cobalt-61 nucleus is 60.9325 amu

Step 2: Calculate binding energy

The mass defect = the difference between the mass of a nucleus and the total mass of its constituent particles.

Cobalt61 has 27 protons and 34 neutrons.

The mass of 27 protons = 27*1.00728 u = 27.19656 u

The mass of 34 neutrons = 34*1.00867 u = 34.29478 u

Total mass of protons + neutrons = 27.19656 u + 34.29478 u = 61.49134 u

Mass of a cobalt61 nucleus = 60.9325 amu

Mass defect = Δm = 0.55884 u

ΔE =c²*Δm

ΔE = $(3.00 *10^8 m/s^2) *(0.55884 amu))*(1.00 g/ 6.02 *10^{23} amu)*(1kg/1000g)=8.36 * 10^{-11} J$

Step 3: Calculate binding energy per nucleon

ΔE $= 8.36* 10^{-11} J$

binding energy $= \frac{8.36* 10^{-11}}{60.9325} J = 1.372 *10^{-12} J$

The binding energy per nucleon $= 1.372 *10^{-12} J$

To learn more about binding energy calculation, click here:

brainly.com/question/14019034

#SPJ4

5 0

2 years ago

NiO is to be reduced to nickel metal in an industrial process by use of the reaction:NiO(s) + CO(g) <-----> Ni(s) + CO2(g)

slavikrds [6]

Answer:

The reaction will occur, in the forward direction, and NiO will be reduced to Ni

Explanation:

Step 1: Data given

Kp = 6.0 * 10²

Pressure of CO = 150 torr

Total pressure never exceeds 760 torr

Step 2: The balanced equation:

NiO(s) + CO(g) ⇆ Ni(s) + CO2(g)

Step 3: Calculate P(CO) and P(CO2)

For this equilibrium, the expression for Kp is:

Kp = P(CO2)/P(CO) = 6.0*10^2

(NiO and Ni are solids so do not change anything to the Kp

⇒ with P(CO) = 150 torr

⇒ P(CO) = 760 - 150 = 610 torr

Step 4: Calculate the reaction quotient

Q = 610/150 = 4.1

Q<<< Kp

There are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

This means the reaction will proceed in the forward direction, and NiO will be reduced to Ni.

6 0

3 years ago

The rate of a reaction is measured by how fast a reactant is used up or how fast a product is formed.

ivanzaharov [21]

This statement is true. The rate of the reaction is measured by how fast a reactant is used up, or how fast a product is formed. This all tie's into the usage of energy.

4 0

3 years ago

A mass of 80 grams of Bromine would be

Elis [28]

I’m pretty sure it’s a

8 0

2 years ago

What is the wavenumber of the radiation emitted when a hydrogen

LUCKY_DIMON [66]

Answer: Wavenumber of the radiation emitted is $0.08\times 10^{8}m^{-1}$

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=\frac{hc}{\lambda}$

where,

E = energy of the radiation = $1.634\times 10^{-18}J$

h = Planck's constant = $6.626\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of radiation = ?

Putting values in above equation, we get:

$1.634\times 10^{-18}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}\\\\\lambda=12.16\times 10^{-8}m$

$\bar {\nu}=\frac{1}{\lambda}=\frac{1}{12.16\times 10^{-8}}=0.08\times 10^{8}m^{-1}$

Thus wavenumber of the radiation emitted is $0.08\times 10^{8}m^{-1}$

8 0

3 years ago