The answer is True because they are formed of deposition.
The percentage of the sulfur (S) in the compound CuSO₄ is 20.1 %.
<h3>What is the mass percentage?</h3>
The percentage of an element in a compound can be determined as the number of parts by mass of that element present in 100 parts by mass of the given compound.
First, calculate the molecular mass of the given compound by the addition of the atomic masses of all the present elements in the molecular formula. Then, the percentage of the elements can be determined by dividing the total mass of the element by the molar mass of the compound multiplied by 100.
Given, the atomic mass of copper, sulfur, and oxygen is 63.55 g, 32.07 g, and 16.0g respectively.
The molecular mass of CuSO₄ = 63.55 + 32.07 + 4(16.0) = 159.62 g
The mass percentage of the sulphur = (32.07/159.62) × 100 = 20.1 %
Therefore, the mass percentage of the sulfur is equal to 20.1 %.
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Answer:
The answer to your question is 0.33 moles of H₃PO₄
Explanation:
Data
moles of Ca(OH)₂ = 0.050
moles of H₃PO₄ = ?
Process
1.- Write the balanced chemical equation
3Ca(OH)₂ + 2H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6H₂O
Reactants Elements Products
3 Ca 3
12 H 12
14 O 14
2.- Calculate the moles of phosphoric acid
3 moles of calcium hydroxide --------------- 2 moles of phosphoric acid
0.5 moles of calcium hydroxide ----------- x
x = (0.5 x 2)/3
x = 0.33 moles
Answer:
D
Explanation:
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