F2 equals 10 N and F4 equals 2 N
Answer:
Mass = 15.20 g of KCl
Explanation:
The balance chemical equation for the decomposition of KClO₃ is as follow;
2 KClO₃ = 2 KCl + 3 O₂
Step 1: Calculate moles of KClO₃ as;
Moles = Mass / M/Mass
Moles = 25.0 g / 122.55 g/mol
Moles = 0.204 moles
Step 2: Find moles of KCl as;
According to equation,
2 moles of KClO₃ produces = 2 moles of KCl
So,
0.204 moles of KClO₃ will produce = X moles of KCl
Solving for X,
X = 2 mol × 0.204 mol / 2 mol
X = 0.204 mol of KCl
Step 3: Calculate mass of KCl as,
Mass = Moles × M.Mass
Mass = 0.204 mol × 74.55 g/mol
Mass = 15.20 g of KCl
Answer:
3.03 g
Explanation:
The first thing to do here is figure out the chemical formula for aluminium hydroxide.
Aluminium is located in group
13
of the periodic table, and forms
3
+
cations,
Al
3
+
. The hydroxide anion,
OH
−
, carries a
1
−
charge, which means that a formula unit of aluminium hydroxide will look like this
[
Al
3
+
]
+
3
[
OH
−
]
→
Al
(
OH
)
3
Now, you can figure out the mass of hydrogen present in
1
mole of aluminium hydroxide by first determining how many moles if hydrogen you get in
1
mole of aluminium hydroxide.
Since
1
mole of aluminium hydroxide contains
3
moles of hydroxide anions, which in turn contain
1
mole of hydrogen each, you can say that you will have
1 mole Al
(
OH
)
3
→
3
a
moles OH
−
→
3
a
moles H
The problem tells you that the molar mass of hydrogen is equal to
1.01 g mol
−
1
. This means that
1
mole of hydrogen has a mass of
1.01 g
.
You can thus say that one mole of aluminium hydroxide contains
3
moles H
⋅
1.01 g
1
mole H
=
a
a
3.03 g H
a
a
∣
∣
I'll leave the answer rounded to three sig figs. Btw my sister calculated this oof
We know that there is 1 mole of Mn for every 1 mole of
KMnO4, therefore the molarity of Mn is similar with KMnO4:
Mn = 0.00300 M
Molar mass of Mn is 54.94 g / mol. Molarity (M) is moles /
L, therefore:
Mn = (0.00300 moles / L) * (54.94 g / mol) * (1000 mg / g)
<span>Mn = 164.82 mg / L = 164.82 ppm</span>
