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2 years ago

The release of energy by the nucleus of an atom as a result of nuclear fission is radiant energy

Physics

1 answer:

Ira Lisetskai [31]2 years ago

5 0

Nuclear Energy
Energy released by nuclear fission or fusion.
So I think the answer is true.

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A 140 N block rests on a table. The suspended mass has a weight of 77 N.

Basile [38]

I'm assuming that this is what your diagram looks like because these types of problems always look like this (lol).

Comment if you need clarification!

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3 years ago

Read 2 more answers

What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod

Inga [223]

Answer:

C) 5ML^2

Explanation:

2 Spheres of mass M

Bug's mass 3M

Rod length 2L, radius L

Find Rotational Inertia I

I=Σmr^2

I=(3M+M+M)L^2

I=5ML^2

6 0

2 years ago

Jose has a mass of 70 kg, what is his weight

rusak2 [61]

His weight would be 154.32

6 0

2 years ago

An object is swung in a horizontal circle on a length of string

Genrish500 [490]

Answer: either 3.20s or 1.18s

Explanation:

4 0

3 years ago

A 16-cm-long straight line connects the center of a turntable to its edge. The turntable rotates counter-clockwise at 45 rpm. A

Bond [772]

Answer:

$\mathbf{V_x = 3.25 \ cm/s}$

$\mathbf{V_y = 1.29\ cm/s}$

Explanation:

Given that:

The radius of the table r = 16 cm = 0.16 m

The angular velocity = 45 rpm

= $45 \times \dfrac{1}{60}(2 \pi)$

= 4.71 rad/s

However, the relative velocity of the bug with turntable is:

v = 3.5 cm/s = 0.035 m/s

Thus, the time taken to reach the bug to the end is:

$t = \dfrac{r}{v}$

$t = \dfrac{0.16}{0.035}$

t = 4.571s

So the angle made by the radius r with the horizontal during the time the bug gets to the end is:

$\theta = \omega t$

$\theta = 4.712 \times 4.571$

$\theta = 21.54^0$

Now, the velocity components of the bug with respect to the table is:

$V_x = Vcos \theta$

$V_x = 0.035 \times cos (21.54^0)$

$V_x = 0.0325 \ m/s$

$\text {V_x = 3.25 \ cm/s}$ $\mathbf{V_x = 3.25 \ cm/s}$

Also, for the vertical component of the velocity $V_y$

$V_y = V sin \theta$

$V_y = 0.035 \times sin (21.54^0)$

$V_y = 0.0129\ m/s$

$\mathbf{V_y = 1.29\ cm/s}$

6 0

3 years ago