Here object is dropped from height "h"
so we can say its initial speed is zero
and it will accelerate downwards due to gravity
now we can say it will take time T to hit the ground
now we can use
![h = v_i*t + \frac{1}{2}gt^2](https://tex.z-dn.net/?f=h%20%3D%20v_i%2At%20%2B%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![h = 0 + \frac{1}{2}*gT^2](https://tex.z-dn.net/?f=h%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2AgT%5E2)
now it is given that it will take 1 second to drop h/2 height to strike the ground
so here we have can say that in "T - 1" s it will cover the h/2 distance from start
![h/2 = 0 + \frac{1}{2}g(T-1)^2](https://tex.z-dn.net/?f=h%2F2%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7Dg%28T-1%29%5E2)
now we can say
![h = g(T-1)^2](https://tex.z-dn.net/?f=h%20%3D%20g%28T-1%29%5E2)
from above two equations we have
![\frac{1}{2}gT^2 = g(T-1)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DgT%5E2%20%3D%20g%28T-1%29%5E2)
![T^2 = 2(T^2 + 1 -2T)](https://tex.z-dn.net/?f=T%5E2%20%3D%202%28T%5E2%20%2B%201%20-2T%29)
![T^2 - 4T + 2 = 0](https://tex.z-dn.net/?f=T%5E2%20-%204T%20%2B%202%20%3D%200)
![T = 3.41 s](https://tex.z-dn.net/?f=T%20%3D%203.41%20s)
now we can find total height of the drop by first equation
![h = \frac{1}{2}gT^2](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B1%7D%7B2%7DgT%5E2)
![h = \frac{1}{2}*9.81*3.41^2](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A9.81%2A3.41%5E2)
![h = 57.2 m](https://tex.z-dn.net/?f=h%20%3D%2057.2%20m)
Answer:
H = 109.2 TJ.
Explanation:
Please see the attachment below.
Answer:(a)does not change
Explanation:
Given
Submarine is 50 m below the surface
Now submarine descends to 100 m and stops
As we know that pressure difference at a depth of h is given by
![P=\rho gh](https://tex.z-dn.net/?f=P%3D%5Crho%20gh)
where
=Density of fluid
g=acceleration due to gravity
h=height below free surface of liquid
buoyant force is equal to volume displaced by object
as the submarine is already in water therefore buoyant force will remain same.
the answer is C the wave is moving horizontally as the particles of the rope move up and down.