Answer:
The percent by mass of nitric acid in the mixture is 11.1 %
Explanation:
Step 1: Data given
Mass of HNO3 = 8.89 grams
Volume of KOH = 27.1 mL = 0. 0271 L
Molarity of KOH = 0.581 M
Step 2: The balanced equation
HNO
3 + KOH → KNO
3 + H
2
O
Step 3: Calculate the moles of KOH
Moles of KOH = molarity KOH * volume
Moles KOH = 0.581 M * 0.0271 L
Moles KOH = 0.0157 moles
Step 4: Calculate moles of HNO3
For 1 mol of KOH we need 1 mol of HNO3
For 0.0157 moles of KOH we need 0.0157 moles of HNO3
Step 5: Calculate mass of HNO3
Mass KOH = moles KOH * molar mass KOH
Mass KOH = 0.0157 moles * 63.01 g/mol
Mass KOH = 0.989 grams
Step 6: Calculate mass % HNO3 in sample
mass % = (0.989 grams / 8.89 grams)*100%
mass % = 11.1 %
The percent by mass of nitric acid in the mixture is 11.1 %
