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Klio2033 [76]
3 years ago
12

What are the concentrations of urea

Chemistry
1 answer:
just olya [345]3 years ago
8 0

Answer: In general, the non-renal causes of increased plasma/serum urea result in a mild to moderate increase (usually no greater than 10.0 mmol/L (BUN 28 mg/dL). Concentration in patients with renal dysfunction can range from mildly increased to severely increased, depending on severity of disease.

Explanation:

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What is earth's crust mainly composed of ​
____ [38]

Answer:

The crust is made of solid rocks and minerals. Beneath the crust is the mantle, which is also mostly solid rocks and minerals, but punctuated by malleable areas of semi-solid magma. At the center of the Earth is a hot, dense metal core.

Explanation:

5 0
3 years ago
Read 2 more answers
Write the formulas for the ionic compounds formed by the following:
PSYCHO15rus [73]

1. KI

2. AlBr₃

3. CsNO₃

4. Al₂(CO₃)₃

Explanation:

1. potassium (K⁺) iodine (I⁻) - KI

2. aluminium (Al³⁺) bromine (Br⁻) - AlBr₃

3. caesium (Cs⁺) nitrate (NO₃⁻) - CsNO₃

4. aluminum (Al³⁺) carbonate (CO₃²⁻)  - Al₂(CO₃)₃

Learn more about:

formulas for the ionic compounds

brainly.com/question/13954262

#learnwithBrainly

7 0
3 years ago
What did Ernest Rutherford s gold foil experiment demonstrate about atoms?
Ghella [55]
-Positively charged nucleus 
-Empty spaced
-Dense core
5 0
3 years ago
What mass of f2 is needed to produce 120. g of pf3 if the reaction has a 78.1% yield?
lesya692 [45]

write the equation for the reaction

that is 6 F2 +P4 =4 PF3

find the theoretical mass that is

let the theoretical yield be represented by y

theoretical yield = 78.1/100 = 120/y

y= 153.6 grams

find the number of moles of  PF3

moles = mass/molar mass

= 153.6/87.97 =1.746 moles

by use of mole ratio between  F2 :PF3 which is 6:4 the moles of F2 is therefore= 1.746 x 6/4 = 2.62 moles

mass = moles x molar mass

= 1.746 moles x38 g/mol = 99.6 grams

6 0
3 years ago
A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
4 0
3 years ago
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