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Grace [21]
4 years ago
14

Or each set of elements represented in this periodic table outline, identify the principal quantum number, n , and the azimuthal

quantum number, ℓ , for the highest energy electrons in an atom of one of those elements.

Chemistry
2 answers:
Ugo [173]4 years ago
8 0

The element are : <u>K, Ne, Xe, Bh and Ce</u>

<h3>Further explanation </h3>

In an atom, there are energy levels in the shell and sub shell.

This energy level is expressed in terms of electron configurations.

Writing the electron configuration starts from the lowest to the highest subshell's energy level. There are 4 sub-shells in an atom's shell, namely s, p, d, and f.

Each sub-shell also has orbitals drawn in the form of a square box in which there are electrons symbolized by half arrows.

Each orbital in an atom consists of 4 quantum numbers

  • n is the principal quantum number ---> describes the size of the orbitals
  • l is the angular momentum / azimuthal quantum number -> describes the shape of the orbitals.
  • ml, the magnetic quantum number -> describes the orientation of orbitals in space
  • ms, the electron-spin quantum number ---> describes the spin of electrons

Value of n: positive integer

value of l: s = 0, p = 1, d = 2, f = 3, ... (n-1)

ml value: between -l to + l

ms value: +1/2 or -1/2

Determining the values ​​of n and l can be obtained from the valence electrons of each element

From attached picture :

1. electron configurations of element ¹⁹K

[Ar] 4s¹ ⇒ n = 4, l = 0

2. electron configurations of element ¹⁰Ne

[He] 2s²2p⁶ ⇒ n = 2, l = 1

3. electron configurations of element ⁵⁴Xe

[Kr]4d¹⁰5s²5p⁶ ⇒ n = 5, l = 1

4. electron configurations of element ¹⁰⁷Bh

[Rn]5f¹⁴6d⁵7s²⇒ n = 7, l = 0

5. electron configurations of element ⁵⁸Ce

[Xe]4f¹5d¹6s² ⇒ n = 6, l = 0

<h3>Learn more  </h3>

element X  

brainly.com/question/2572495  

electrons and atomic orbitals  

brainly.com/question/1832385  

Identify the group number in the periodic table  

brainly.com/question/2014634

Tems11 [23]4 years ago
5 0
The answer is potassium. It would be 4, and for neon would be 2. Just total which row of the periodic table you are on. The "L" tells you whether the highest-energy electron is in an "s" orbital (L=0) or a "p" orbital (L=1) or a "d" orbital (L=2) or an "f" orbital (L=3). The way in which these orbitals are filled is: for each of the first three rows (up to argon), two electrons in the "s" orbital are filled first, then 6 electrons in the "p"orbitals. The row where the potassium also starts with filling the "s" orbital at the new "n" level (4) but then goes back to satisfying up the "d" orbitals of n=3 before it seals up the "p"s for n=4.
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A company wants to sell more sports drinks so they decide to add more sugar. For Group A they
ycow [4]

Answer:

Group B

Explanation:

The control group of an experiment is considered to be the "normal" because it does not receive the expeiemental treatment and hence is used to compare with the experimental group. The control and experimental groups are similar in every other aspect with the exception of the "INDEPENDENT VARIABLE". The independent variable is not changed in the control group.

In this experiment, the control group is GROUP B, which was given a plain gatorade without adding sugar. Sugar is the independent variable here, and it was not included in GROUP B, meaning that GROUP B is the CONTROL GROUP. On the other hand, the experimental group is the GROUP A.

8 0
4 years ago
In a coffee-cup calorimeter, 1.60 g of NH4NO3 was mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolu
jekas [21]

Answer:

Explanation:

mass of the solution m = 1.6 + 75 = 76.6 g

fall in temperature = 25 - 23.34 = 1.66°C

heat absorbed = mass x specific heat x fall in temperature

= 76.6 x 1.66 x 4.18

= 531.5 J .

= .5315 kJ .

mol weight of ammonium nitrate = 80 g

heat absorbed by 1.6 g = .5315 kJ

heat absorbed by 80 g or one mole = 26.575 kJ

enthalpy change ΔH = +26.575 kJ

b )

enthalpy of hydration = 2630 kJ / mol

lattice energy = enthalpy of hydration + enthalpy change

= 2630 + 26.575

= 2656.575 kJ  .

7 0
3 years ago
A 475 ml sample of a gas was collected at room temperature of 23.5 °C and a pressure of
Molodets [167]

Answer:

The volume when the conditions were altered is 0.5109 L or 510.9 mL

Explanation:

Using the general gas equation,

P1 V1 / T1 = P2 V2 / T2

where;

P1 = 756 mmHg

V1 = 475 ml = 0.475 L

T1 = 23.5°C = 23.5 + 273K = 275.5 K

P2 = 722 mm Hg

T2 = 10°C = 10 + 273 K = 283 K

V2 = ?

Rearranging to make V2 the subject of the formula, we obtain:

V2 = P1 V1 T2 / P2 T1

V2 = 756 * 0.475 * 283 / 722 * 275.5

V2 = 101, 625.3 / 198911

V2 = 0.5109 L or  510.9 mL

3 0
4 years ago
How many mole are in 14.5 grams of neon please explain
a_sh-v [17]

Answer:

0.725 moles

Explanation:

Use the mole = mass/mr equation to find the moles.

Mole = 14.5/20 (Neon's Mr) = 0.725 Moles

3 0
3 years ago
Define a catalyst. [2 marks]​
svp [43]

Answer:

a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change

6 0
4 years ago
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