Answer:
Explanation:
Please check the picture and consider straight lines
The answer is slightly left and slightly right of the curved end of the horseshoe.
Answer:
The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is <u>10°.</u>
Explanation:
Given:
Mass of the driver is, 
Radius of circular turn is, 
Linear speed of the car is, 
Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.
The forces are:
1. Weight = 
2. Centripetal force, 'F', which is given as:

Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,
°
Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.
Answer:
The blue light
Explanation:
Spectrums of visible light with longer wavelength are absorbed more quickly such as red than those with shorter wavelength. This contributes to why blue with higher energy and shorter wavelength is able to penetrate deeply compared to others that are easily absorbed. Blue light persist longer so it reaches the depth first while so of others are absorbed.
Answer:
Given that
For A weight Wt= 22.7 N
m₁ = 22.7/10 = 2.27 kg
Force alone inclined plane
Wt₁ = m₁ g sin θ
Wt₁ =22.7 sin 17.2°
Wt₁ = 6.7 N
For B weight Wt₂= 34.5-N
m₂ = 3.45 kg
coefficient of friction ,μ= 0.219
θ = 17.2 degree
The friction force on the block A
Fr= μ m₁ g cos θ
Fr= 0.216 x 22.7 x cos 17.2°
Fr= 4.68 N
Lets take acceleration of system is a m/s²
Tension = T
From Newtons law
Wt₂ - Wt₁ - Fr = (m₁ +m₂) a
34.5 - 6.7 - 4.68 = (2.27 + 3.45 ) a
a= 4.05 m/s²
Block B
Wt₂ - T = m₂ a
T = 34.5 - 4.05 x 3.45
T= 20.52 N