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2 years ago

If the girl skater has a mass of 30 kg and moves backward at 5 m/s, what is the velocity or the boy skater

1 answer:

3 0

Question: Two people stand facing each other at a roller-skating rink then push off each other. If the girl skater has a mass of 30 kg and moves backward at 5 m/s, what is the velocity of the boy skater if his mass is 50 kg?

Answer:

3 m/s

Explanation:

Applying,

The Law of conservation of momentum

Momentum of the girl skater = momentum of the boy skater

MV = mv...................... Equation 1

Where M = mass of the girl skater, V = velocity of the girl skater, m = mass of the boy skater, v = velocity of the boy skater

From the question, we were asked to calculate v

v = MV/m.................. Equation 1

Given: M = 30 kg, V = 5 m/s, m = 50 kg

Substitute these values into equation 1

v = (30×5)/50

v = 3 m/s

Hence the velocity of the the boy skater is 3m/s

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3 years ago

Find the distance in nm between two slits that produces the first minimum for 410-nm violet light at an angle of 14.5°.

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2 years ago

Read 2 more answers

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Answer:

A. The applied force should be the same size as the friction force

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<u>A. The applied force should be the same size as the friction force</u>

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