Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the true population mean textbook weight.
Number of sample, n = 22
Mean, u = 64 ounces
Standard deviation, s = 5.1 ounces
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
64 ± 1.645 × 5.1/√22
= 64 ± 1.645 × 1.087
= 64 ± 1.788
The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces
The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces
Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces
Answer:
x=5
Step-by-step explanation:
Since both of these length are equal, 6x+4=8x-6, 2x=10, x=5
X=5 because 2x plus 6x equals 8x and then when you divide the 40 by 8 u get 5
The initial amount of $ in the count is $40 every year she earns 5% so what we ant to do is find 5% of 40 which is 2, 40+2=42
the answer is $42
I got the answer 3n^2 + 4 but that isn’t one of the listed options. take a look at my working out.
