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Maurinko [17]
3 years ago
8

Why do gases act more ideal at lower pressures?

Chemistry
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

Gases act more ideal at lower pressure <u>beacuse</u><u> </u><u>t</u><u>he</u><u> </u><u>attractive</u><u> </u><u>forces</u><u> </u><u>between</u><u> </u><u>molecules</u><u> </u><u>will</u><u> </u><u>decrease</u><u> </u><u>or</u><u> </u><u>become</u><u> </u><u>less</u><u> </u><u>significant</u><u> </u><u>compared</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>empty</u><u> </u><u>space</u><u> </u><u>between</u><u> </u><u>them</u><u>.</u>

Explanation:

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure as the potential energy due to intermolecular forces becomes less significant compared with the particles "kinetic energy" and the size of the molecules become less significant compared to the empty space between them.

Attractive forces between molecules, decrease the pressure of a reak gas, slowing the molecules and reducing collisions with the walls.The higher the value of a gas, the greater the attraction between molecules and the more easily the gas will compress.

<h2>HOPE IT HELPS MUCH</h2>

answered by: <em><u>J</u></em><em><u>o</u></em><em><u>h</u></em><em><u>n</u></em><em><u> </u></em><em><u>Glenly</u></em><em><u> </u></em><em><u>Pillazo</u></em><em><u> </u></em><em><u>M</u></em><em><u>a</u></em><em><u>h</u></em><em><u>u</u></em><em><u>s</u></em><em><u>a</u></em><em><u>y</u></em>

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g aqueous barium hydroxide (ba(oh)2) and nitric acid (hno3) participate in a complete neutralization reaction. in the molecular
Whitepunk [10]

Answer:

Where the products are H2O and Ba(NO3)2

Explanation:

A base, as, barium hydroxide (Ba(OH)2) reacts with an acid (HNO3), producing water (H2O), and the related salt (Ba(NO3)2) in a reaction called <em>neutralization reaction.</em>

The balanced reaction is:

Ba(OH)2 + 2 HNO3 → 2 H2O + Ba(NO3)2

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4 0
3 years ago
atch the following aqueous solutions with the appropriate letter from the column on the right. fill in the blank 1 A 1. 0.20 m N
Firdavs [7]

Answer:

Highest boiling point - 0.43 m Urea

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Explanation:

We know that;

ΔT = kb m i

Where;

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For NiSO4 , NH4I  and NH4NO3 , the Van't Hoff factor, i = 2

But for Urea, the Van't Hoff factor, i = 1

We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.

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Answer:

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3 years ago
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F = kQ₁Q₂/d²
where
k is equal to 9×10⁹ N·m²/C²
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d is the distance between them

For this problem, Q₁ = +2(0.16×10⁻¹⁸ C) and Q₂ = -2(0.16×10⁻¹⁸ C), because a single electron or proton has a charge of 0.16×10⁻¹⁸ C. The distance between the two ions is the sum of their radii.
d = radius of Ca²⁺ + radius of O²⁻
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F = (9×10⁹ N·m²/C²)(+2(0.16×10⁻¹⁸ C))(-2(0.16×10⁻¹⁸ C))/(0.238×10⁻⁹ m)²
F = 1.017×10¹¹ N

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