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Maurinko [17]
3 years ago
8

Why do gases act more ideal at lower pressures?

Chemistry
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

Gases act more ideal at lower pressure <u>beacuse</u><u> </u><u>t</u><u>he</u><u> </u><u>attractive</u><u> </u><u>forces</u><u> </u><u>between</u><u> </u><u>molecules</u><u> </u><u>will</u><u> </u><u>decrease</u><u> </u><u>or</u><u> </u><u>become</u><u> </u><u>less</u><u> </u><u>significant</u><u> </u><u>compared</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>empty</u><u> </u><u>space</u><u> </u><u>between</u><u> </u><u>them</u><u>.</u>

Explanation:

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure as the potential energy due to intermolecular forces becomes less significant compared with the particles "kinetic energy" and the size of the molecules become less significant compared to the empty space between them.

Attractive forces between molecules, decrease the pressure of a reak gas, slowing the molecules and reducing collisions with the walls.The higher the value of a gas, the greater the attraction between molecules and the more easily the gas will compress.

<h2>HOPE IT HELPS MUCH</h2>

answered by: <em><u>J</u></em><em><u>o</u></em><em><u>h</u></em><em><u>n</u></em><em><u> </u></em><em><u>Glenly</u></em><em><u> </u></em><em><u>Pillazo</u></em><em><u> </u></em><em><u>M</u></em><em><u>a</u></em><em><u>h</u></em><em><u>u</u></em><em><u>s</u></em><em><u>a</u></em><em><u>y</u></em>

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1. A sulfur atom has 16 protons, 18 neutrons, and 16
Gnom [1K]

Answer:

b. 16 protons, 18 neutrons, and 18 electrons

Explanation:

Things to be remembered

Negative charge on any ionic species indicates gained the electrons

Positive charge on any ionic species indicates lost the electrons

A sulfur atom has 16 protons, 18 neutrons, and 16 electrons, A sulfide ion has a 2– charge which indicates that sulphur has gained two electron from any other atom, ion or species!

<em><u>Thanks for joining brainly community!</u></em>

8 0
3 years ago
Read 2 more answers
a compound contains 32 grams of O for every 2.0 grams of H. What is the most likely molecular formula of this compound?
Vedmedyk [2.9K]

Answer:

H₂O₂

Explanation:

The molecular formula gives the exact number of atoms within a chemical compound.

In this problem:

Mass of O  = 32g

Mass of H = 2g

  Let us follow this methodical approach to solve the problem:

Elements                                  O                                       H

Mass                                         32                                      2

Molar mass                               16                                       1

Number of moles                  32/16                                     2/1        

                                                  2                                         2

The molecular formula of the compound is H₂O₂                

4 0
3 years ago
a mixture of oxygen, hydrogen, and nitrogen gases exerts a total pressure of 282 kpa. if the partial pressures of oxygen and hyd
dimaraw [331]
Pressures oxygen and hydrogen +  pressure nitrogen

110 Kpa + 106 Kpa = 216 Kpa

Partial pressure:

total pressure -  exerted by nitrogen:

282 Kpa - 216 Kpa

= 66 Kpa

hope this helps!
7 0
3 years ago
Read 2 more answers
What is the formula for finding the density of<br> an object?
TEA [102]
The answer would be:
D = M/V

D=Density
M= mass
V= volume
3 0
4 years ago
Read 2 more answers
Two hundred kg of liquid contains 30% butane, 40% pentane, and the rest hexane (mass %) Determine: The mole fraction composition
OlgaM077 [116]

Answer:

The mole fraction composition of the liquid is :

Mole fraction of butane, pentane and hexane are 0.3638,0.3908 and 0.2454 respectively.

Explanation:

Mass of the liquid mixture = 200 g

Percentage of butane = 30%

Mass of butane = \frac{30}{100}\times 200 g=60 g

Moles of butane = n_1=\frac{60 g}{58 g/mol}=1.0345 mol

Percentage of pentane= 40%

Mass of pentane= \frac{40}{100}\times 200 g=80 g

Moles of pentane= n_2=\frac{80 g}{58 g/mol}=1.1111 mol

Percentage of hexane = 100% - 30% - 40% = 30%

Mass of hexane = \frac{30}{100}\times 200 g=60 g

Moles of hexane = n_2=\frac{60 g}{86 g/mol}=0.6977 mol

Mole fraction of butane, pentane and hexane : \chi_1, \chi_2 \& \chi_3

\chi_1=\frac{n_1}{n_1+n_2+n_3}=\frac{1.0345 mol}{1.0345 mol+1.1111 mol+0.6977 mol}=0.3638

\chi_2=\frac{n_2}{n_1+n_2+n_3}=\frac{1.1111 mol}{1.0345 mol+1.1111 mol+0.6977 mol}=0.3908

\chi_3=\frac{n_1}{n_1+n_2+n_3}=\frac{0.6977 mol}{1.0345 mol+1.1111 mol+0.6977 mol}=0.2454

4 0
4 years ago
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