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posledela
4 years ago
9

If radioactive caesium was reacted with chlorine, would you expect the caesium chloride produced to be radioactive? Explain you

answer.
Chemistry
2 answers:
CaHeK987 [17]4 years ago
8 0

Answer:  The answer is YES.

Explanation:  Isotopic substitution is the kind of substitution in which the present active species is replaced by its isotope in order to check the reactivity of the given species.

Radioactive substitution is also the same kind of substitution in which the active species is replaced by its radioactive isotope.

Thus, in cesium chloride when radioactive cesium is reacted with the chlorine, then the product formed cesium chloride is expected to be radioactive because radioactivity or isotopic substitution has nothing to do with the bonding. Only outermost electrons of the cesium has been transferred from cesium to chlorine , and its nucleus has not been affected in the same process.

aniked [119]4 years ago
3 0
Yes due to the radioactivity having nothing to do with the chemical equation given it will release radiation at a rate determined by it's half life.
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What is the correct name of the compound Mn3(PO4)2? A. manganese phosphate B. manganese(I) phosphate C. manganese(III) phosphate
Sergio039 [100]
The correct name of the compound Mn3(PO4)2 is  definitely the last option represented above <span>D. manganese(II) phosphate. I am pretty sure this answer will help you

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3 0
3 years ago
A common fuel additive that is composed of C, H, and O enhanced the performance of gasoline began being phased out in 1999 becau
spayn [35]

Answer:

C₅ H₁₂ O

Explanation:

44 g of CO₂ contains 12 g of C

30.2 g of CO₂ will contain 12 x 30.2 / 44 = 8.236 g of C .

18 g of H₂O contains 2 g of hydrogen

14.8 g of H₂0 will contain 1.644 g of  H .

total compound = 12.1 out of which 8.236 g is C and 1.644 g is H , rest will be O

gram of O = 2.22

moles of C, O, H in the given compound =  8.236 / 12 , 2.22 / 16 , 1.644 / 1

= .6863 , .13875 , 1.644

ratio of their moles = 4.946 : 1 : 11.84

rounding off to digits

ratio = 5 : 1 : 12

empirical formula = C₅ H₁₂ O

6 0
3 years ago
What is the maximum mass of P2I4 that can be prepared from 8.80g of P4O6 and 12.37g of iodine according to the reaction:
Dvinal [7]
The balanced chemical reaction would be as follows:

<span>5P4O6 +8I2 ---> 4P2I4 +3P4O10

We are given the amount of reactants used for the reaction. We first need to determine the limiting reactant from the given amounts. We do as follows:

8.80 g P4O6 (1 mol / </span><span>219.88 g) = 0.04 mol P4O6
12.37 g I2 ( 1 mol / </span><span>253.809 g ) = 0.05 mol I2

Therefore, the limiting reactant is iodine since less it is being consumed completely in the reaction. We calculate the amount of P2I4 prepared as follows:

0.05 mol I2 ( 4 mol P2I4 / 8 mol I2 ) (</span><span>569.57 g / 1 mol) = 14.24 g P2I4</span>
8 0
3 years ago
Read 2 more answers
Que diferencia hay entre drogas estimuladoras depresoras y perturbadoras del sistema nervioso
12345 [234]

Answer:

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Por último, las drogas perturbadoras del sistema nervioso incluyen LSD, cannabis o la cocaína. Algunos efectos típicos son cambios en la visión y el oído, alucinaciones, confusión de sentidos, fuertes experiencias de belleza, disolución del yo y un sentido de unidad, experiencias religiosas y confrontaciones con el subconsciente. Este tipo de drogas son en su gran mayoría ilegales, y no forman parte de tratamientos médicos autorizados.

3 0
3 years ago
Consider the reaction.
Stella [2.4K]

Answer:

when the rates of the forward and reverse reactions are equal

Explanation:

In a chemical system, the reaction reaches a dynamic equilibrium when the rate of formation of product equals the rate of formation of reactants. This implies that both the forward and revered(backwards) reaction are occurring at the same rate.

5 0
3 years ago
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