The answer for the following problem is mentioned below.
- <em><u>Therefore the mass of an object is 14.16 grams.</u></em>
Explanation:
Force:
The push or pull on an object with mass that cause change in the velocity
It is a vector quantity.
The formula to calculate the force is:
F = m × a
Given:
Force (F) = -136 N
acceleration (a) = -9.6 m/s^2
To calculate:
mass of the object (m)
We know that,
<em>F = m × a</em>
where,
F represents the force of the object
m represents mass of an object
a is acceleration of an object
From the equation;
-136 = m × -9.6
m = 
m = 14.16 grams
<em><u>Therefore the mass of an object is 14.16 grams.</u></em>
Answer:
The response can be defined as follows:
Explanation:
ATP is a hydrolysis energy-saving money of the cell. It is used to support the cell's endothermic processes.
![ATP\ +\ H_{2}O\ \rightleftharpoons \ ADP\ +\ P_{i}\\\\Q\ = \ \frac{[ADP][P_{i}]}{[ATP][H_{2}O]}\\\\ADP= 0.250 \ M\\\\P_i = 0.010 \ M\\\\ATP = 0.150 \ M\\\\H_2O = 55.55 \ M\\\\\Delta G \ =\ \Delta G^{o}\ +\ 2.303\ RT\ \log\ Q\\\\R = 8.314 \frac{J}{mol\ K}\\\\T = 298\ K\\\\](https://tex.z-dn.net/?f=ATP%5C%20%2B%5C%20H_%7B2%7DO%5C%20%5Crightleftharpoons%20%5C%20ADP%5C%20%2B%5C%20P_%7Bi%7D%5C%5C%5C%5CQ%5C%20%3D%20%5C%20%5Cfrac%7B%5BADP%5D%5BP_%7Bi%7D%5D%7D%7B%5BATP%5D%5BH_%7B2%7DO%5D%7D%5C%5C%5C%5CADP%3D%200.250%20%5C%20M%5C%5C%5C%5CP_i%20%3D%200.010%20%5C%20M%5C%5C%5C%5CATP%20%3D%200.150%20%5C%20M%5C%5C%5C%5CH_2O%20%3D%2055.55%20%5C%20M%5C%5C%5C%5C%5CDelta%20G%20%5C%20%3D%5C%20%5CDelta%20G%5E%7Bo%7D%5C%20%2B%5C%202.303%5C%20RT%5C%20%5Clog%5C%20Q%5C%5C%5C%5CR%20%3D%208.314%20%5Cfrac%7BJ%7D%7Bmol%5C%20K%7D%5C%5C%5C%5CT%20%3D%20298%5C%20%20K%5C%5C%5C%5C)
Answer:
It would get <u>colder</u>
Explanation:
The lattice energy is the energy involved in the disruption of interactions between the ions of the salt. In this case, we have: ΔHlat = 350 kJ/mol > 0, so it is an endothermic process (the energy is absorbed).
The solvation energy is the energy involved in forming interactions between water molecules and the ions of the salt. In this case, we have: ΔHsolv = 320 kJ/mol > 0, so it is an endothermic process (the energy is absorbed).
The dissolution process involve both processes: the disruption of ion-ion interactions of the salt and the solvation process. Thus, the enthalphy change (ΔHsol) in the preparation of the solution is calculated as the addition of the lattice energy and solvation energy:
ΔHsol= ΔHlat + ΔHsolv = 350 kJ/mol + 320 kJ/mol = 370 kJ/mol
370 kJ/mol > 0 ⇒ endothermic process
Since the preparation of the solution is an <u>endothermic</u> process, it will absorb energy from the surroundings, so <u>the solution would get colder</u>.
The molarity of the HCl is 1 M when 12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution.
Explanation:
Data given:
molarity of the base NaOH, Mbase =0. 5 M
volume of the base NaOH, Vbase = 12 ml
volume of the acid, Vacid = 6 ml
molarity of the acid, Macid = ?
The titration formula for acid and base is given as:
Mbase Vbase = Macid Vacid
Macid =
Macid = 1 M
we can see that 1 M solution of HCl was used to neutralize the basic solution of NaOH. The volume of NaOH is 12 ml and volume of HCl used is 6ml.
Answer:
A)
Cl + O3 --> ClO + O2
2ClO --> ClOOCl
ClOOCl --> 2 Cl + O2
B)
Cl2 + 4O3 -> 2 ClO + 5O2
Explanation:
Step 1: Chlorine atoms react with ozone (O3) to form chlorine monoxide and molecular oxygen
Cl + O3 --> ClO + O2
Step 2: Chlorine monoxide molecules combine to form ClOOCl gas
2ClO --> ClOOCl
Step 3: ClOOCl absorbs sunlight and breaks into chlorine atoms and molecular oxygen
ClOOCl --> 2 Cl + O2
B) Overall Balanced equation
Cl2 + 4O3 -> 2 ClO + 5O2
