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Hunter-Best [27]
3 years ago
7

What is the length of x of the side of the triangle below?

Physics
1 answer:
Anna [14]3 years ago
4 0
The answer is c. I hope it’s clear

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1. Which of the following best describes the movement of an object at rest if no outside forces act on it?
Mariulka [41]
C.It will stay at rest due to inertia
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3 years ago
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Before using a string in a comparison, you can use either the To Upper method or the To Lower method to convert the string to up
diamong [38]

Answer:

True, check attachment for code

Explanation:

To convert java strings of text to upper or lower case, we can use and inbuilt methods To Uppercase and To lower case.

The first two lines of code will set up a String variable to hold the text "text to change", and then we print it out.

The third line sets of a second String variable called result.

The fourth line is where the conversion is done.

We can compare the string

We can compare one string to another. (When comparing, Java will use the hexadecimal values rather than the letters themselves.) For example, if we wanted to compare the word "Fat" with the word "App" to see which should come first, you can use an inbuilt string method called compareTo.

Check attachment for the code

3 0
3 years ago
Brainliest for correct answer :)
AnnyKZ [126]
All 3 objects have the same mass
8 0
3 years ago
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Given that the CFL bulb is rated at 10% efficiency, if the LED bulb consumes half the amount of electrical power, for the same a
Butoxors [25]

Answer and explanation:

The efficiency of the LED bulb is 20% while The efficiency of the Inc bulb is 1%.

The lightbulb efficiency can be defined as the quotient between the amount of usable light and the amount of electrical power output. For the efficiency of the CFL Bulb:

\epsilon_{CFL}=\frac{L_0}{P_0}=0.1

Therefore:

\epsilon_{led}=\frac{L_0}{0.5P_0}=2 \cdot0.1=0.2\\\epsilon_{INC}=\frac{L_0}{10P_0}=0.1 \cdot 0.1=0.01

4 0
3 years ago
PLEASE HELP ME WITH THIS ONE QUESTION
shtirl [24]

Answer:

\lambda=1.39\times 10^{-4}\ s^{-1}

Explanation:

Given that,

The half-life of Barium-139 is 4.96\times 10^3

A sample contains 3.21\times 10^{17} nuclei.

We need to find the decay constant for this decay. The formula for half life is given by :

T_{1/2}=\dfrac{0.693}{\lambda}\\\\\lambda=\dfrac{0.693}{T_{1/2}}

Put all the values,

\lambda=\dfrac{0.693}{4.96\times 10^3}\\\\=1.39\times 10^{-4}\ s^{-1}

So, the decay constant is 1.39\times 10^{-4}\ s^{-1}.

4 0
3 years ago
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