All categories

3 years ago

to move a heavy object, like a refrigerator which one of the following would not help to decrease the friction force?

2 answers:

8 0

Use round wheels to roll the heap, help the weight by evacuating appended or contained protests, or place a smoother surface betwen the question and the floor. Water or different liquids can be utilized to diminish the protection, yet just on the off chance that they stay between the question and the floor.

exis [7]3 years ago

8 0

Answer:

Use more force to push the refrigerator with the help of a friend

Explanation:

You might be interested in

1. If Randy races his F-150 down Highway 1 for 2560 meters in 60 seconds, what is his average speed?

Nimfa-mama [501]

The average speed is 42.7 m/s

Explanation:

The speed of an object in uniform motion (=moving at constant speed) is given by the equation:

$v=\frac{d}{t}$

where

v is the speed

d is the distance

t is the time

For the car in this problem, we have:

d = 2560 m (distance)

t = 60 s (time)

Solving the equation, we find the average speed:

$v=\frac{2560}{60}=42.7 m/s$

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

4 0

3 years ago

Plants grow over time by balancing two chemical reactions: photosynthesis and cellular respiration. Plants use the products of p

Andreyy89

The answer to that I think would be D because:

A is wrong because it doesn't make sense the way the order it is in,

B doesn't make sense because it is in the wrong order, and

C says the same exact thing that photosynthesis says which would mean that it is representing the photosynthesis equation not the chemical equation for cellular respiration.

Also it is D because D shows the correct way that the chemical equation representing cellular respiration is supposed to be in.

Hope this helped!

8 0

3 years ago

One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0.70 times the mass of our sun. This planet

Stels [109]

0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.

Answer: Option B

<u>Explanation:</u>

Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

$\frac{G M m}{r^{2}}=m \omega^{2} r$

The orbit’s period is given by,

$T=\sqrt{\frac{2 \pi}{\omega r^{2}}}=\sqrt{\frac{r^{3}}{G M}}$

Where,

$T_{e}$ = Earth’s period

$T_{p}$ = planet’s period

$M_{s}$ = sun’s mass

$r_{e}$ = earth’s radius

Now,

$T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}$

As, planet mass is equal to 0.7 times the sun mass, so

$T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}$

Taking the ratios of both equation, we get,

$\frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}$

$\frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}$

Given $T_{p}=9.5 \text { days }$ and $T_{e}=365 \text { days }$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{365}{9.5}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=\left(\frac{133225}{90.25} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=(2108.82)^{\frac{1}{3}}$

$r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}$

7 0

3 years ago

Is it raining anywhere else because it is about to start pouring where I live

Rudiy27

she is idiot gehfehdgfgs bsbwhejxkdjfkdjdjdgddjs

4 0

2 years ago

Read 2 more answers

A flask is filled with 1.57 L (L: liter) of a liquid at 90.6 °C. When the liquid is cooled to 10.2 °C, its volume is only 1.38 L

nydimaria [60]

The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

<h3>What is the coefficient of volume expansion of the liquid?</h3>

The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.

As we know, The coefficient of volume expansion of the liquid

= change in volume/(original volume × temperature difference)

= (V₂ - V₁)/[V₁ × (T₂ - T₁)]

Change in volume = (V₂ - V₁)

Here, V₂ ( final volume) = 1.31 L

V₁ (initial volume)= 1.55 L

T₂ (final temperature) = 14.7 degrees

T₁ (initial temperature) = 96 degrees

The coefficient of volume expansion of the liquid

= (1.31 - 1.55) / [1.5 × (14.7- 96)]

= 1.97 × 10⁻³ /⁰C

Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

To know more about coefficient of volume expansion refer to:

brainly.com/question/24042303

#SPJ1

8 0

1 year ago