Answer:
The answer to your question is 24.32 g
Explanation:
Data
Atomic weight = ?
HCl volume = 125 ml
Molarity = 0.2
mass of metal = 0.304 g
Balanced chemical equation
M + 2HCl ⇒ MCl₂ + H₂
Process
1.- Calculate the moles of HCl
Molarity = moles / volume (L)
- Solve for moles
moles = Molarity x volume
moles = 0.2 x 0.125
= 0.025
2.- Calculate the moles of the Metal
1 mol of M ----------------- 2 moles of HCl
x ----------------- 0.025 moles of HCl
x = (0.025 x 1) / 2
x = 0.0125 moles of HCl
3.- Calculate the atomic weight of the metal
atomic weight ---------------- 1 mol
0.304 g ---------------0.0125 moles
Atomic weight = (1 x 0.304) / 0.0125
Atomic weight = 24.32 g
Ok I’m figuring this one out
Atomic weight of a Platinum:
195.078 u = 195.078 * 1.66 * 10^(-27) kg = 3.2382948 * 10^(-25) kg
m ( Pt ) = 3.2382948 * 10^(-25) * 5.35 * 10^(21) =
= 1.732488 * 10^(-3) kg = 1.732448 g
Answer:
"hydrogen to oxygen"
Explanation:
Hydrogen bonds are formed when hydrogen is bonded to highly electronegative element such as Chlorine, fluorine, oxygen etc.
In hydrogen bonding, the hydrogen atom of one molecule of water is attracted to the oxygen atom of another molecule of water via permanent dipole-dipole interaction.
Hence, If you have 2 water molecules together, they always sit "hydrogen to oxygen" as a result of dipole - dipole interaction and hydrogen bonding between water molecules.
Reaction of
Acyl Halides with
Grignard reagent results in the formation of
Ketones in first step. While in second step reaction of Grignard reagent with Ketones results in the formation of
Tertiary Alcohols.
If you want to
stop the reaction at
Ketone stage then you are required to use another
mild reactive organometallic compound. In our case we will use Organocuprates.
Organocuprates are also known as Gilman Reagents. These reagents does not add to ketones, aldehydes and esters but they can add to acid halides to produce Ketones.