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laila [671]
3 years ago
9

A weather balloon containing helium with a volume of 410.0 L rises in the atmosphere and is cooled from 17∘

Chemistry
1 answer:
likoan [24]3 years ago
3 0

Answer:

V₂ = 1500 Liters ( 2 sig. figs.)

Explanation:

Given the following gas law variables:

P₁ = 110.0KPa           P₂ = 25KPa

V₁ = 410 Liters          V₂ = ?

T₁ = 17°C ( = 290K)   T₂ = -27°C  ( = 248K)

P₁V₁/₁T₁ = P₂V₂/T₂  =>  V₂ = V₁(P₁/P₂)(T₂/T₂)

V₂ = 410L(110.0KPa/25KPa)(248k/290K) = 1542 L (calc. ans.)

V₂ = 1500 Liters ( 2 sig. figs.)

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How many cm in 725 km?
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The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are
Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>

For the zero-order reactions, concentration-time equation can be written as follows:

                                          [A] = - Kt + [Ao]

where:

  • [A]: concentration of the reactant A at the <em>t </em>time,
  • [A]o: initial concentration of the reactant A,
  • K: rate constant,
  • t: elapsed time of the reaction

<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>

Data:

K = 4.2 ×10−3atm/s,  

[A]o=[HBr]o= 2 atm,  

[A]=[HBr]=0 atm (all HBr(g) is gone)

<em>We clear the incognita :</em>

[A] = - Kt + [Ao]............. Kt =  [Ao] - [A]

                                        t  = ([Ao] - [A])/K

<em>We replace the numerical values:</em>

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0
2 years ago
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2.3*10^24 atoms

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6 0
2 years ago
How many moles would there be in 20.0 g of sodium chloride?
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Answer:

20.0/1 x 1mole/58.44=0.34

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Been a minute since I've done this, but this is how I remember doing it, soo..hope this helps!

6 0
2 years ago
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