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NISA [10]
2 years ago
11

A 1.0KW kettle contains 500g of boiling water. Calculate the time needed to evaporate all the water in the kettle. (Specific lat

ent heat of vaporization of water=2.26MJKG^-1
Physics
1 answer:
Free_Kalibri [48]2 years ago
6 0

The time needed to evaporate all the water in the kettle is  1.13 x 10³s.

<h3>What is Power?</h3>

The power is defined as the the ratio of amount of energy produced per unit time.

P =E/t

Energy is in the form of heat gained to evaporate all water in kettle.

E = Q =mL

So, P = mL/t

Substitute mass of water m = 0.5kg,  latent heat of vaporization of wate L = 2.26 x 10⁶ J/kg, power P= 10³ W, we have

10³ = (0.5 x 2.26 x 10⁶) /t

t = 1.13 x 10³s

Thus, the time needed to evaporate all the water is  1.13 x 10³s.

Learn more about power.

brainly.com/question/21334428

#SPJ1

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