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slavikrds [6]
3 years ago
11

The following reaction is an example of what type of equilibrium reaction?

Chemistry
1 answer:
Mrac [35]3 years ago
6 0

Hello, Brainly User!

A heterogeneous equilibrium reaction is when there are different phases in the reaction. An equilibrium reaction is a reaction that can go in both the forward and reverse directions, and the concentrations of the reactants and products remain the same.

So therefore, your answer is A. Heterogeneous!

Hope i helped and i was honored to answer your question!

Have a great day..

-Philaeagles14

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Which explains the information needed to calculate speed and velocity?
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Answer:

Both require time, but velocity requires displacement and speed requires distance

Explanation:

For calculating speed we require time and distance because speed is defined as the distance per unit time and as speed is a scalar quantity it does not have any direction

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3 years ago
Calculate how many times more soluble Mg(OH)2 is in pure water Based on the given value of the Ksp, 5.61×10−11, calculate the ra
maks197457 [2]

Answer:

molar solubility in water = 2.412 * 10^-4  mol/L

molar solubility of NaOH in 0.130M = 3.32 * 10^-9 mol/L

Mg(OH)2 is a factor 0.73*10^5 more soluble in pure water than in 0.130 M NaOH

Explanation:

The Ksp refers to the partial solubilization of a mostly insoluble salt. This is an equilibrium process.

 

The equation for the solubilization reaction of Mg(OH)2 can be given as:

 

Mg(OH)2 (s) → Mg2+ (aq) + 2OH– (aq)

 Ksp can then be given as followed:

Ksp = [Mg^2+][OH^–]²  

<u>Step 2:</u> Calculate the solubility in water

Mg(OH)2 (s) → Mg2+ (aq) + 2OH– (aq)

The mole ratio Mg^2+ with OH- is 1:2

So there will react X of Mg^2+ and 2X of OH-

The concentration at equilibrium will be XM Mg^2+ and 2X OH-

Ksp = [Mg^2+][OH^–]²  

5.61*10^-11 = X * (2X)² = X *4X² = 4X³

 X = <u>2.412 * 10^-4 mol/L = solubility in water</u>

<u>Step 3</u>: Calculate solubility in 0.130 M NaOH

The initial concentration of Mg^2+  = 0 M

The initial concentration of OH- = 0.130 M

The mole ratio Mg^2+ with OH- is 1:2

So there will react X of Mg^2+ and 2X +0.130 for OH-

The concentration at equilibrium will be XM Mg^2+ and 0.130 + 2X OH-

The value of "[OH–] + 2X" is, because the very small value of X, equal to the value of [OH–] .

Let's consider:

[Mg+2] = X

[OH] = 0.130

Ksp = [Mg^2+][OH^–]²  

5.61*10^-11 = X *(0.130)²  

5.61*10^-11 = X * (0.130)^2

X = <u>3.32*10^-9 = solubility in 0.130 M NaOH </u>

<u>Step 4:</u> Calculate how many times Mg(OH)2 is better soluble in pure water.

(2.412*10^-4)/ (3.32*10^-9) = 0.73 * 10^5

Mg(OH)2 is a factor 0.73*10^5 more soluble in pure water than in 0.130 M NaOH

4 0
3 years ago
Interpret the block diagram seen here. Arranging the letters from oldest to youngest, the order should be
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Answer: option B. - A, B, D, E, C, H, F, G is correct using the principle of cross-cutting relationships.

The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through.

Explanation:

The full sequence of events is:

1. Layer A formed.

2. Layer B formed

3. Layer D formed.

4. Layer E formed

5. After layers A-B-D-E were present, intrusion C cut across all three.

6. Fault H formed, shifting rocks E through A and intrusion C.

7. Weathering and erosion created a layer of soil on top of layer F then G.

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