Answer:
F(x) = 0 ; x < 0
0.064 ; 0 ≤ x < 1
0.352 ; 1 ≤ x < 2
0.784 ; 2 ≤ x < 3
1 ; x ≥ 3
Explanation:
Each wafer is classified as pass or fail.
The wafers are independent.
Then, we can modelate X : ''Number of wafers that pass the test'' as a Binomial random variable.
X ~ Bi(n,p)
Where n = 3 and p = 0.6 is the success probability
The probatility function is given by :
Where 
is the combinatorial number
Let's calculate f(x) :
For the cumulative distribution function that we are looking for :
The cumulative distribution function for X is :
F(x) = 0 ; x < 0
0.064 ; 0 ≤ x < 1
0.352 ; 1 ≤ x < 2
0.784 ; 2 ≤ x < 3
1 ; x ≥ 3
Answer and Explanation:
Pyroelectric material
Pyroelectric materials have special property of generating potential difference (although it is very less ) when these material are treated with heat or when celled down.
The potential difference generated is for very less time
The generation of potential difference is due to change in position of atoms after heating or cooling.
Diode logic gates are not suitable for cascading operation because the pull-down or pull-up resistance within makes them a high output resistance device.
<h3>What is a
cascading operation?</h3>
A cascading operation can be defined as a process which involves the use of a circuit breaker's current-limiting capacity in order to enable an installation of lower-rated and lower-cost circuit breakers.
According to the National Electrical Code (NEC), diode logic gates are not suitable for cascading operation because the pull-down or pull-up resistance within makes them a high output resistance device.
Read more on National Electrical Code here: brainly.com/question/10619436
#SPJ1
Answer:
clc
clear
x = input('type value of angle in degrees:\n');
x = x*pi/180; %convverting fron degree to radian
sin_x = x; %as first term of taylor series is x
E = 1; %just giving a value of error greater than desired error
n = 0;
while E > 0.000001
previous = sin_x;
n = n+1;
sin_x = sin_x + ((-1)^n)*(x^(2*n+1))/factorial(2*n+1);
E = abs(sin_x - previous); %calculating error
end
a = sprintf('sin(x) = %1.6f',sin_x);
disp(a)
Explanation:
Answer:
★ The answers ARE B,A,D,D,A !
Explanation:
Hope you have a great day
