Answer:
Electroosmotic velocity will be equal to 
Explanation:
We have given applied voltage v = 100 volt
Length of capillary L = 5 mm = 0.005 m
Zeta potential of the capillary surface 
Dielectric constant of glass is between 5 to 10 here we are taking dielectric constant as 
Viscosity of glass is 
Electroosmotic velocity is given as 
So Electroosmotic velocity will be equal to
Answer:
Following the ways of dealing with incomplete questions, i was able to get the complete question, please look at the attachment for ans.
Answer:
a) 1 m^3/Kg
b) 504 kJ
c) 514 kJ
Explanation:
<u>Given </u>
-The mass of C_o2 = 1 kg
-The volume of the tank V_tank = 1 m^3
-The added energy E = 14 W
-The time of adding energy t = 10 s
-The increase in specific internal energy Δu = +10 kJ/kg
-The change in kinetic energy ΔKE = 0 and The change in potential energy
ΔPE =0
<u>Required </u>
(a)Specific volume at the final state v_2
(b)The energy transferred by the work W in kJ.
(c)The energy transferred by the heat transfer W in kJ and the direction of
the heat transfer.
Assumption
-Quasi-equilibrium process.
<u>Solution</u>
(a) The volume and the mass doesn't change then, the specific volume is constant.
v= V_tank/m ---> 1/1= 1 m^3/Kg
(b) The added work is defined by.
W =E * t ---> 14 x 10 x 3600 x 10^-3 = 504 kJ
(c) From the first law of thermodynamics.
Q - W = m * Δu
Q = (m * Δu) + W--> (1 x 10) + 504 = 514 kJ
The heat have (+) sign the n it is added to the system.
Answer:
Explanation:
There are three points in time we need to consider. At point 0, the mango begins to fall from the tree. At point 1, the mango reaches the top of the window. At point 2, the mango reaches the bottom of the window.
We are given the following information:
y₁ = 3 m
y₂ = 3 m − 2.4 m = 0.6 m
t₂ − t₁ = 0.4 s
a = -9.8 m/s²
t₀ = 0 s
v₀ = 0 m/s
We need to find y₀.
Use a constant acceleration equation:
y = y₀ + v₀ t + ½ at²
Evaluated at point 1:
3 = y₀ + (0) t₁ + ½ (-9.8) t₁²
3 = y₀ − 4.9 t₁²
Evaluated at point 2:
0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²
0.6 = y₀ − 4.9 t₂²
Solve for y₀ in the first equation and substitute into the second:
y₀ = 3 + 4.9 t₁²
0.6 = (3 + 4.9 t₁²) − 4.9 t₂²
0 = 2.4 + 4.9 (t₁² − t₂²)
We know t₂ = t₁ + 0.4:
0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)
0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))
0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)
0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)
0 = 2.4 − 3.92 t₁ − 0.784
0 = 1.616 − 3.92 t₁
t₁ = 0.412
Now we can plug this into the original equation and find y₀:
3 = y₀ − 4.9 t₁²
3 = y₀ − 4.9 (0.412)²
3 = y₀ − 0.83
y₀ = 3.83
Rounded to two significant figures, the height of the tree is 3.8 meters.
Answer:if power factor =1 is possible for that.
Explanation:when pf is unity. means 1.
