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Answer:
a) 2.933 m
b) 4.534 m
Explanation:
We're given the equation
v(t) = -0.4t² + 2t
If we're to find the distance, then we'd have to integrate the velocity, since integration of velocity gives distance, just as differentiation of distance gives velocity.
See attachment for the calculations
The conclusion of the attachment will be
7.467 - 2.933 and that is 4.534 m
Thus, The distance it travels in the second 2 sec is 4.534 m
Answer:
241.8 N.
Explanation:
The force on branch provides a reaction to the ape's weight force plus the centripetal force needed to keep the gibbon in a circular motion of radius 0.60 m.
Centripetal force = mv^2/r
F = mg + mv²/r
F = m(g + v²/r)
where,
m = mass
= 9 kg
g = acceleration due to gravity
= 9.8 m/s²
v = 3.2 m/s
r = 0.60 m
F = 9 * (9.8 + 3.2²/0.60)
= 241.8 N.
Answer:
0.0443 m/s
Explanation:
= Mass of honeybee = 0.15 g
= Mass of popsicle stick = 4.75 g
= Velocity of honeybee
= Velocity of stick = 0.14 cm/s
In this system the linear momentum is conserved

The velocity of the bee is 4.43 cm/s or 0.0443 m/s