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2 years ago

Which of the following equations

Chemistry

2 answers:

yKpoI14uk [10]2 years ago

6 0

I think it might be C

Maslowich2 years ago

5 0

Your answer will be C

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If I add 5.0 mL of water to 8.0 mL of a 6.0M NaOH solution, what

erastova [34]

Answer:fdfgfdgfdgfdgfd

Explanation:

3 0

3 years ago

Tính phân tử khối của chất Al(OH3)

Anton [14]

Answer:

78g/mol

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8 0

2 years ago

What is a common use of bases?

Fittoniya [83]

A common use of bases is to reduce indigestion. Hence, option D is correct.

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

Bases are substances whose solutions have a pH value of more than 7. Bases are bitter in taste.

Whereas acids are the substances whose solutions have a pH value of less than 7. Acids are sour in taste.

When an excess of acid is formed in the human stomach then an antacid tablet which is basically a base is consumed that helps in reducing indigestion.

Therefore, we can conclude that the common use of bases is to reduce indigestion.

Learn more about the base here:

brainly.com/question/1432645

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3 0

1 year ago

How many moles are in 8.32 times 1024 molecules of CO2

Svetradugi [14.3K]

Answer:

13.8 mol CO₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

8.32 × 10²⁴ molecules CO₂

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

$8.32 \cdot 10^{24} \ molecules \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ molecules \ CO_2} )$ = 13.816 mol CO₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

13.816 mol CO₂ ≈ 13.8 mol CO₂

3 0

3 years ago

A sample of chlorine gas occupies a volume of 707 ml at 2.90 atm. What is the new pressure in torr if the volume is compressed t

dolphi86 [110]

Answer:

The new pressure is 3850 torr.

Explanation:

The relation between volume and pressure is inverse as per Boyle's law. Its mathematical form is given by :

$P_1V_1=P_2V_2$

Here,

$P_1=2.9\ atm$

$V_1=707\ mL$

$V_2=0.533\ L$

Let $P_2$ is the new pressure. So using Boyle's law we get :

$P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{2.9\times 707}{0.533}\\\\P_2=3846.71\ \text{torr}$

$P_2=3850\ \text{torr}$

So, the new pressure is 3850 torr.

3 0

3 years ago