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3 years ago

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A glass rod was charged positively by rubbing it with neutral silk, then the rod was touched to the top of a neutral electroscop

e. Which picture above depicts this situation?
Question 7 options:

A

B

C

D

1 answer:

Leto [7]3 years ago

5 0

D is ur answer bc th ngeavtixe would pull the electric or

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PLZ PLZ PLZZZZZZZ HELP ASAP!!!

AlladinOne [14]

i belive the answe is c and if im wrong im tarrably sorry

7 0

4 years ago

Read 2 more answers

New attempt is in progress. Some of the new entries may impact the last attempt grading. Incorrect. The hammer throw is a track-

Morgarella [4.7K]

This question involves the concepts of centripetal force, range of projectile and projectile motion.

The magnitude of centripetal force is "2812.8 N".

First, we will find the velocity of the ball by using the formula of the range of the projectile.

$R = \frac{v^2Sin2\theta}{g}$

where,

R = range of projectile = 86.75 m

v = speed = ?

θ = launch angle = 47.9°

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$86.75\ m = \frac{(v)^2Sin(2)(47.9^o)}{9.81\ m/s^2}\\\\v = \sqrt{\frac{(86.75\ m)(9.81\ m/s^2)}{Sin95.8^o}}$

v = 29.25 m/s

Now, we will use the formula to find out the centripetal force:

$F_c = \frac{mv^2}{r}$

where,

$F_c$ = Centripetal Force = ?

m = mass of the ball = 7.3 kg

v = speed = 29.25 m/s

r = radius = 2.22 m

Therefore,

$F_c = \frac{(7.3\ kg)(29.25\ m/s)^2}{2.22\ m}$

<u>Fc = 2812.8 N = 2.812 KN</u>

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Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

5 0

3 years ago

What is a precipitate?

Lunna [17]

Rain is considered a precipitate. Along with: drizzle, sleet, snow and hail.

hope this helps :)

7 0

4 years ago

Read 2 more answers

In a Broadway performance, an 83.0-kg actor swings from a R = 3.90-m-long cable that is horizontal when he starts. At the bottom

Veseljchak [2.6K]

Answer:

$h = 2.821\,m$

Explanation:

The speed of the actor before the collision is found by means of the Principle of Energy Conservation:

$(83\,kg)\cdot(9.807\,\frac{m}{s})\cdot (3.90\,m) = \frac{1}{2}\cdot (83\,kg)\cdot v^{2}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (3.90\,m)}$

$v \approx 8.746\,\frac{m}{s}$

The speed after the inelastic collision is obtained by using the Principle of Momentum Conservation:

$(83\,kg)\cdot (8.746\,\frac{m}{s} )+(55\,kg)\cdot (0\,\frac{m}{s} ) = (83\,kg + 55\,kg)\cdot v$

$v = 5.260\,\frac{m}{s}$

Lastly, the maximum height is determined by using the Principle of Energy Conservation again:

$\frac{1}{2}\cdot (138\,kg)\cdot (5.260\,\frac{m}{s} )^{2} = (138\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot h$

$h = \frac{(5.260\,\frac{m}{s} )^{2}}{9.807\,\frac{m}{s^{2}} }$

$h = 2.821\,m$

8 0

4 years ago

A student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.6 m in a time of 4.0 s. Fi

Korvikt [17]

The average speed of the ball is 0.15 m/s.

The average speed of the ball can be calculated using the formula below.

<h3 /><h3> Average speed: </h3>

This is the ratio of the total distance to the total time traveled by a body

<h3 /><h3>Formula:</h3>

S = d/t.................. Equation 1

<h3>Where:</h3>

S = Average speed
d = total distance
t = total time.

From the question,

<h3>Given:</h3>

d = 0.6 m
t = 4.0 s

Substitute these values into equation 1

S = 0.6/4
S = 0.15 m/s

Hence, the average speed of the ball is 0.15 m/s.

Learn more about average speed here: brainly.com/question/4931057

8 0

2 years ago