A 200 kg object is initially at rest on a horizontal frictionless surface. At time t = 0 , a horizontal force of 100 N applied t
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Answer:
Explanation:
We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.
<h3>1. Force of 1st Object </h3>First, we can find the force of the first, 8 kilogram object.
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.
- m= 8 kg
- a= 1.6 m/s²
Substitute these values into the formula.
Multiply.
Now, use the force we just calculated to complete the second part of the problem. We use the same formula:
This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.
- F= 12.8 kg *m/s²
- m= 2 kg
Substitute the values into the formula.
Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.
The units of kilograms cancel.
The acceleration is 6.4 meters per square second.