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timofeeve [1]
3 years ago
8

An athlete in the early weeks of an aerobic training program develops a decreased hemoglobin concentration but does not report d

isproportionate fatigue. Which of the following statements is true of the athlete's decreased hemoglobin levels? a. Vitamin and mineral supplements are necessary to reverse this condition. b. Decreased hemoglobin concentrations are never a cause for concern. c. Vitamin and mineral supplements are necessary to reverse this condition d. The athlete has a low blood volume. e. The athlete has an iron deficiency.
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer: B

Explanation: Hemoglobin is a protein in red blood cells that acts as the vehicle for oxygen and carbon dioxide from the lungs to tissues and vice-versa.

What is considered normal Hemoglobin levels vary throughout one's life, from childhood to adult life and in older adults. It even varies between women and men. In women, it also varies depending on whether they are pregnant or not.

When hemoglobin does become less than normal, it results in anemia, a condition accompanied by fatigue. Because the athlete does not have this symptom, he is not suffering from anemia, and so there is no cause for concern. Although the athlete's hemoglobin level has reduced, the absence of fatigue indicates that it is not lower than normal.

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Determine the approximate force (N) used to pull a sled up a 400 m hill using 1900 J of work.
Sergeu [11.5K]
The work done to pull the sled up to the hill is given by
W=Fd
where
F is the intensity of the force
d is the distance where the force is applied.

In our problem, the work done is W=1900 J and the distance through which the force is applied is d=400 m, so we can calculate the average force by re-arranging the previous equation and by using these data:
F= \frac{W}{d}= \frac{1900 J}{400 m} = 4.75 N \sim 5 N
4 0
4 years ago
Water is pumped steadily out of a flooded basement at a speed of 5.4 m/s through a uniform hose of radius 0.83 cm. The hose pass
Gala2k [10]

To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.

The work done would be defined as

\Delta W = \Delta PE + \Delta KE

Where,

PE = Potential Energy

KE = Kinetic Energy

\Delta W = (\Delta m)gh+\frac{1}{2}(\Delta m)v^2

Where,

m = Mass

g = Gravitational energy

h = Height

v = Velocity

Considering power as the change of energy as a function of time we will then have to

P = \frac{\Delta W}{\Delta t}

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

The rate of mass flow is,

\frac{\Delta m}{\Delta t} = \rho_w Av

Where,

\rho_w = Density of water

A = Area of the hose \rightarrow A=\pi r^2

The given radius is 0.83cm or 0.83 * 10^{-2}m, so the Area would be

A = \pi (0.83*10^{-2})^2

A = 0.0002164m^2

We have then that,

\frac{\Delta m}{\Delta t} = \rho_w Av

\frac{\Delta m}{\Delta t} = (1000)(0.0002164)(5.4)

\frac{\Delta m}{\Delta t} = 1.16856kg/s

Final the power of the pump would be,

P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)

P = (1.16856)((9.8)(3.5)+\frac{1}{2}5.4^2)

P = 57.1192W

Therefore the power of the pump is 57.11W

6 0
3 years ago
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8 0
4 years ago
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3 years ago
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An incompressible fluid (water) is flowing through a pipe of diameter 20 cm with
sergey [27]

Answer:

115 kPa

Explanation:

Use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Assuming no elevation change, h₁ = h₂.

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P = 115,000 Pa

P = 115 kPa

3 0
3 years ago
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