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3 years ago

Energy transferred as heat always moves from an object

1 answer:

3 0

Well, if we are being technical, yes and the only reason I say yes is because the sun is a hot gas rock. And it gives off UV rays which is heat on earth. So, yes. It does

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The relatively small, rocky bodies generally found orbiting between mars and jupiter are known as _____.

ivolga24 [154]

Asteroids; <span>The relatively small, rocky bodies generally found orbiting between Mars and Jupiter are known as asteroids.</span>

3 0

3 years ago

Read 2 more answers

An alpha particle (a He nucleus, containing two protons and two neutrons and having a mass of 6.64×10−27 kg ) traveling horizont

victus00 [196]

Answer:

A) d = 1.38 10-3 m, B) the velocity modulus remains constant and the velocity direction changes since the force is perpendicular

c) a = 1.94 10¹² m / s

d) the force is perpendicular to these two, that is, it points out of the page (positive z-axis)

e) E) the modulus of velocity remains constant because the force is perpendicular to the movement,

Explanation:

A) Let's use Newton's second law for this problem where the force is the magnetic force given by

F = m a

The magnetic force is

F = q v x B = q v B sin θ

Where the angle between the speed and the magnetite field is ce 90º so the sin 90 = 1

This implies that the acceleration is centripetal, which is given by

a = v² / R

We substitute

q v B = m v² / r

r = m v / qB

Let's calculate

r = 6.64 10⁻²⁷ 36.6 10³ / (2 1.6 10⁻¹⁹ 1.10)

r = 6,904 10⁻⁴ m

Diameter is twice the radius

d = 2 r

d= 1.38 10-3 m

B) The effect of the magnetic field is that the particle describes a circular motion, where the velocity modulus remains constant and the velocity direction changes since the force is perpendicular

C) the centripetal acceleration is

F = m a

q v B = m a

a = q v B / m

Let's calculate

a = 2 1.6 10⁻¹⁹ 36.6 10³ 1.10 / 6.64 10⁻²⁷

a = 1.94 10¹² m / s

D) Acceleration has the same direction of force toward the center of the circular orbit,

If we assume that the horizontal direction of the alpha particle is on the x-axis, the field is on the positive y-axis, so the force is perpendicular to these two, that is, it points out of the page (positive z-axis)

E) the modulus of velocity remains constant because the force is perpendicular to the movement, but the direction of the velocity does change in the direction of the force

6 0

3 years ago

If you calculate W, the amount of work it took to assemble this charge configuration if the point charges were initially infinit

sp2606 [1]

Answer:

W = 0×(kq2L)

Explanation:

We know that the work to assemble a charge configuration of two charges a distance r from each other is simply W = kq2/r

If we want to assemble three charges A, B, and C. It's necessary to consider the distances between them

WABC = kq2/(rAB + rAC + rBC)

So, to assemble four charges A, B, C, & D....

WABCD = kq2/(rAB + rAC + rAD + rBC + rBD + rCD)

Considering a square charge configuration with sides L, such as in figure attached A, B, & C are positive & D is negative

rAB = L

rAC = L√2

rAD = L (-)

rBC = L

rBD = L√2 (-)

rCD = L (-)

⇒ W = kq2/(L + L√2 + (-L) + L + (-L√2) + (-L)

⇒ ∴ W = 0 × (kq2/L)

This way, working through each option...

(a)

The positive charges are equidistant from each other at a distance of L.

rAB = L

rAC = L

rAD = ½L⋅sin(60) (-)

rBC = L

rBD = ½L⋅sin(60) (-)

rCD = ½L⋅sin(60) (-)

Wa = kq2/(3L - (3/2)L⋅(0.866))

⇒ ∴ Wa = (1/1.7) × (kq2/L) = (0.5879)× (kq2/L)

(b)

rAB = L

rAC = 2L

rAD = 3L (-)

rBC = L

rBD = 2L (-)

rCD = L (-)

Wb = kq2/(4L - 6L)

⇒ ∴ Wb = (-1/2) × (kq2/L) = (-0.5)× (kq2/L)

(c)

The factor doesn't matter, so Wc = 0 × (kq2/L)

In this case, the greater work is actually the less work. Therefore, the positive work represents the amount of work the system actually exhibits, that we don't have to do. If there is negative work, we have to make up that work in order to place the charges as desired.

This way, charge configuration (a) requires the least amount of work.

5 0

3 years ago

Could a mixture be made only element and no compounds

Veseljchak [2.6K]

Take the tiny bit of carbon dioxide and the tiny bit of water vapor out of the air,
and the rest of what you're breathing right now is a mixture of elements.

4 0

3 years ago

Juan and Kuri are on a carousel. Juan is closer to the center of the carousel than Kuri. Which statement describes their tangent

Licemer1 [7]

Answer:

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

Explanation:

Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution

As we know that the distance moved in one revolution is given as

$d = 2\pi r$

also the time period of revolution for both will remain same as they move with the time period of carousel

Now we can say that the speed is given as

$v = \frac{2\pi r}{T}$

so Juan will have less tangential speed. so correct answer will be

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

6 0

3 years ago

Read 2 more answers