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Shtirlitz [24]
3 years ago
13

Which of the following would not be considered hot work? A chipping B soldering C

Engineering
1 answer:
tankabanditka [31]3 years ago
5 0
I believe the answer is D: brazing
Hope this helps you have a good night
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What is 12 cm theodolite​
Klio2033 [76]

Answer:

Answer below :)

Explanation:

<u>SIZE OF THEODOLITE:</u> A theodolite is designated by diameter of the graduated circle on the lower plate. The common sizes are 8 cm to 12 cm while<em> 14 cm</em> to <em>25 cm</em> instrument are used for triangulation work.

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Speed limit signs are classified as
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Answer:

B. Regulatory signs

Explanation:

traffic rules

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Ammonia gas is diffusing at a constant rate through a layer of stagnant air 1 mm thick. Conditions are such that the gas contain
fiasKO [112]

Answer:

The solution to this question is 5.153×10⁻⁴(kmol)/(m²·s)

That is the rate of diffusion of ammonia through the layer is

5.153×10⁻⁴(kmol)/(m²·s)

Explanation:

The diffusion through a stagnant layer is given by

N_{A}  = \frac{D_{AB} }{RT} \frac{P_{T} }{z_{2} - z_{1}  } ln(\frac{P_{T} -P_{A2}  }{P_{T} -P_{A1} })

Where

D_{AB} = Diffusion coefficient or diffusivity

z = Thickness in layer of transfer

R = universal gas constant

P_{A1} = Pressure at first boundary

P_{A2} = Pressure at the destination boundary

T = System temperature

P_{T} = System pressure

Where P_{T} = 101.3 kPa P_{A2} =0, P_{A1} =y_{A}, P_{T} = 0.5×101.3 = 50.65 kPa

Δz = z₂ - z₁ = 1 mm = 1 × 10⁻³ m

R =  \frac{kJ}{(kmol)(K)} ,    T = 298 K   and  D_{AB} = 1.18 \frac{cm^{2} }{s} = 1.8×10⁻⁵\frac{m^{2} }{s}

N_{A} = \frac{1.8*10^{-5} }{8.314*295} *\frac{101.3}{1*10^{-3} }* ln(\frac{101.3-0}{101.3-50.65}) = 5.153×10⁻⁴\frac{kmol}{m^{2}s }

Hence the rate of diffusion of ammonia through the layer is

5.153×10⁻⁴(kmol)/(m²·s)

5 0
3 years ago
Which two statements about professional technical jobs in the energy industry are correct?
Tanya [424]
The answer is both B and D
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3 years ago
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Write an expression that evaluates to true if the value of variable lastName is greater than the string Dexter.
gregori [183]

Answer:

lastName.compareTo("Dexter")>0

Explanation:

The expression that evaluates to true if the value of variable lastName is greater than the string Dexter is; lastName.compareTo("Dexter")>0.

4 0
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