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weeeeeb [17]
2 years ago
13

Time left 0:35:32 Three steel rod (E = 200 GPa) supports 36 KN Load P. Each of the rods AB and CD has a 200 mm? cross- sectional

area and rod EF has 625 mm2 cross-sectional area. C D Compute for the stress in the rod. AB. a. 15.25 MPa b. 38.10 MPa C 19.05 MPa d. 30.50 MPa​
Engineering
1 answer:
taurus [48]2 years ago
8 0

Answer:

tama po ba

Explanation:

correct me if im wrong

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The water in an 8-m-diameter, 3-m-high above-ground swimming pool is to be emptied by unplugging a 3-cm-diameter, 25-m-long hori
Dima020 [189]

Answer:

The maximum discharge rate of water is 4.6 L/s

Explanation:

Given data:

d=diameter=8 m

h=height=3 m

The mathematical expression for the theoritical velocity is:

v_{th} =\sqrt{2gh} =\sqrt{2*9.8*3} =7.6681m/s

The maximum discharge can be calculate by:

Q=C_{d} Av_{th}

Here

Cd=coefficient of discharge=0.855

Q=0.855*\frac{\pi }{4} *d^{2} *vx_{th} =0.855*\frac{\pi }{4} *0.03^{2} *7.6681=0.0046m^{3} /s=4.6L/s

8 0
3 years ago
Hi, everyone I'm a high school student in Texas. My engineering teacher is asking us to find an active engineer to complete a li
jenyasd209 [6]

Answer:ill look it up

Explanation:

6 0
2 years ago
You are an engineer working in a auto crash test lab. Some members of your team have raised objections against the use of cadave
Nikolay [14]

Answer: Application.

Explanation:

The question on wether to contine the use of cadavers in the lab for test is being centered around its application. Cadaver which is same as a corpse or dead body is used in crash site during automobil test in lab, some of this cadavers are been disrespected with their applications in the automobile industries because many didn’t consent to be used in those experiments or test.

5 0
3 years ago
Write a function named "total_population" that takes a string then a list as parameters where the string represents the name of
adelina 88 [10]

Answer:

Return the total population of all cities in the list.

Explanation:

It is for every element in cityinfo. It works not only for one array but multiple.

I attached the document with the code or function with the name import cvs becuase when I wrote it down and it sent a message written on red about inappropriate words.

Download docx
5 0
3 years ago
A block of ice weighing 20 lb is taken from the freezer where it was stored at -15"F. How many Btu of heat will be required to c
Rus_ich [418]

Answer:

Heat required =7126.58 Btu.

Explanation:

Given that

Mass m=20 lb

We know that

1 lb =0.45 kg

So 20 lb=9 kg

m=9 kg

Ice at -15° F and we have to covert it at 200° F.

First ice will take sensible heat at up to 32 F then it will take latent heat at constant temperature and temperature will remain 32 F.After that it will convert in water and water will take sensible heat and reach at 200 F.

We know that

Specific heat for ice C_p=2.03\ KJ/kg.K

Latent heat for ice H=336 KJ/kg

Specific heat for ice C_p=4.187\ KJ/kg.K

We know that sensible heat given as

Q=mC_p\Delta T

Heat for -15F to 32 F:

Q=mC_p\Delta T

Q=9\times 2.03(32+15) KJ

Q=858.69 KJ

Heat for 32 Fto 200 F:

Q=mC_p\Delta T

Q=9\times 4.187(200-32) KJ

Q=6330.74 KJ

Total heat=858.69 + 336 +6330.74 KJ

Total heat=7525.43 KJ

We know that 1 KJ=0.947 Btu

So   7525.43 KJ=7126.58 Btu

So heat required to covert ice into water is 7126.58 Btu.

8 0
3 years ago
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