Question

Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là

Answer 1

Answer: The mass of $FeO$ required is 14.37 g

Explanation:

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$ ......(1)

We are given:  

Molarity of iron (II) sulfate = 1 M

Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol$

The chemical equation for the reaction of FeO with sulfuric acid follows:

$FeO+H_2SO_4\rightarrow FeSO_4+H_2O$

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = $\frac{1}{1}\times 0.200=0.200mol$ of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We know, molar mass of $FeO$ = 71.84 g/mol

Putting values in above equation, we get:

$\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g$

Hence, the mass of $FeO$ required is 14.37 g