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wariber [46]
3 years ago
5

when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2

.0×10^-5k^-1, calculate its original volume​
Physics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

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meriva

<em>False</em>

Explanation:

The electrons cloud patterns are extremely complex and is of no importance to the discussion of electric charge in the atom. More important is the fact that electrons are labile; that is, they can be <em>transferred</em> from one atom to the next. It is through electronic transfer that atoms become charged.

6 0
3 years ago
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If someone ways 600 newtons and the shoes have an area of 300cm squared, what pressure does he exert on the ground?
lukranit [14]
Pressure = Force / Area

Put your data in front of yourself.

Force = 600 Newtons
Area = 300 cm^2

Firstly you need to convert the area into m^2 and you do this by diving 300 with 10000.

Now you use the formula:-
Pressure = 600/ 0.03
Which comes out to be 20,000 Pa.

Hope this helps!
4 0
3 years ago
A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made
olga55 [171]

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

B=\dfrac{\mu_oI}{2\pi r}

B=\dfrac{4\pi \times 10^{-7}\times 0.2\ A}{2\pi \times 0.02\ m}

B = 0.000002 T

B=10^{-5}\ T

(2) Exact formula:

B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }

B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }

B = 0.00000199 T

or

B = 0.000002 T

Hence, this is the required solution.

4 0
3 years ago
What is the acceleration of a block on a ramp inclined 35o to the horizontal if µk = 0.4?
lina2011 [118]
We can solve the problem by applying Newton's second law, which states that the resultant of the forces acting on an object is equal to the product between its mass and its acceleration:
\sum F = ma

We should consider two different directions: the direction perpendicular to the inclined plane and the direction parallel to it. Let's write the equations of the forces along the two directions, decomposing the weight of the object (mg):

mg \sin \theta - \mu_K N = ma (parallel direction) (1)
mg \cos \theta - N =0 (perpendicular direction) (2)
where
\theta=35^{\circ} is the angle of the inclined plane, N is the normal reaction of the plane, \mu_K N is the frictional force, with \mu_K=0.4 being the coefficient of friction.

From eq.(2), we find
N=mg \cos \theta
and if we substitute into eq.(1), we can find the acceleration of the block:
mg \sin \theta - \mu_k mg \cos \theta = ma
from which
a=g(\sin \theta - \mu_K \cos \theta)=(9.81 m/s^2)(\sin 35^{\circ} - 0.4 \cos 35^{\circ})=2.41 m/s^2
7 0
3 years ago
A boy sledding down a hill accelerates at 1.40 m/s². If
mrs_skeptik [129]

Answer: He would reach 7m/s at the distance of 17,5m.

Explanation: In order for us to know how long it takes for the speed to be reached, we use the equation V= Vo + at, with V=7m/s, Vo= 0m/s since you start from rest and a=1.4m/s². T is the time in seconds that we want to find out.

7 = 0 + 1.4t

7 = 1.4t

t= 5s

Now, we want to know the distance this boy reaches in 5 seconds, in a 7m/s speed and accelarating in 1.4m/s². For finding this out, we use another equation, S = So + Vot + (at²)/2, S being the final distance, So = 0m because he started from rest, and the other variables used before.

S = 0 + 0*5 + [1.4*(5²)]/2

S = 0 + 0 + (1.4*25)/2

S = 35/2

S = 17,5m

5 0
3 years ago
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