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Sholpan [36]
3 years ago
11

If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he

at capacity of the metal?
Physics
2 answers:
kobusy [5.1K]3 years ago
8 0

sorry i don't know the answer i'm really sorry

forsale [732]3 years ago
6 0
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q= mC_s \Delta T
where m is the mass of the substance, Cs is its specific heat capacity and \Delta T is the increase of temperature.

If we re-arrange the formula, we get
C_s =  \frac{Q}{m \Delta T}
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
C_s =  \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C
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The formula that can be used to obtain a convergent series is given by;

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1 year ago
Earth’s atmosphere is in hydrostatic equilibrium. What this means is that the pressure at any point in the atmosphere must be hi
Misha Larkins [42]

Answer: The pressure that one experiences on the Mount Everest will be different from the one, in a classroom. It is because pressure and height are inversely proportional to each other. This means that as we move up, the height keeps on increasing but the pressure will keep on decreasing. This is the case that will be observed when one stands on the Mount Everest as the pressure is comparatively much lower there.

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6 0
3 years ago
What force must the worker exert to get the box moving &amp; what force must the worker exert to accelerate the box at 0.1 meter
photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

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now we can write the equation of net force as

F - F_k = m*a

here

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3 0
3 years ago
When water is boiled under a pressure of 2.00atm, the heat of vaporization is 2.20×106J/kg and the boiling point is 120∘C. At th
Vikki [24]

Answer:

2033219.05 J

Explanation:

V = Volume

P = Pressure = 2 atm

m = Mass of water = 1 kg

L_v = Heat of vaporization = 2.2\times 10^6\ J/kg

Work done in an isobaric system is given by

W=-P\Delta V\\\Rightarrow W=-2\times 101325\times (1\times 10^{-3}-0.824)\\\Rightarrow W=166780.95\ J

Work done is 166780.95 J

Change in internal energy is given by

\Delta U=Q-W

Heat is given by

Q=mL_v\\\Rightarrow Q=1\times 2.2\times 10^6\\\Rightarrow Q=2.2\times 10^6\ J

\Delta U=2.2\times 10^6-166780.95\\\Rightarrow \Delta U=2033219.05\ J

The increase in internal energy of the water is 2033219.05 J

6 0
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