Rocks in the Earth's mantle contain a higher percentage of _______ and _______ than do rocks in the Earth's crust.
2 answers:
You might be interested in
Answer:
the work done to lift the bucket = 3491 Joules
Explanation:
Given:
Mass of bucket = 10kg
distance the bucket is lifted = height = 11m
Weight of rope= 0.9kg/m
g= 9.8m/s²
initial mass of water = 33kg
x = height in meters above the ground
Let W = work
Using riemann sum:
the work done to lift the bucket =∑(W done by bucket, W done by rope and W done by water)
=
Work done in lifting the bucket (W) = force × distance
Force (F) = mass × acceleration due to gravity
Force = 9.8 * 10 = 98N
W done by bucket = 98×11 = 1078 Joules
Work done to lift the rope:
At Height of x meters (0≤x≤11)
Mass of rope = weight of rope × change in distance
= 0.8kg/m × (11-x)m
W done = integral of (mass×g ×distance) with upper 11 and lower limit 0
W done =
Note : upper limit is 11 not 1, problem with math editor
W done = 7.84 (11x-x²/2)upper limit 11 to lower limit 0
W done = 7.84 [(11×11-(11²/2)) - (11×0-(0²/2))]
=7.84(60.5 -0) = 474.32 Joules
Work done in lifting the water
At Height of x meters (0≤x≤11)
Rate of water leakage = 36kg ÷ 11m = kg/m
Mass of rope = weight of rope × change in distance
= kg/m × (11-x)m = 3.27kg/m × (11-x)m
W done = integral of (mass×g ×distance) with upper 11 and lower limit 0
W done =
Note : upper limit is 11 not 1, problem with math editor
W done = 32.046 (11x-x²/2)upper limit 11 to lower limit 0
W done = 32.046 [(11×11-(11²/2)) - (11×0-(0²/2))]
= 32.046(60.5 -0) = 1938.783 Joules
the work done to lift the bucket =W done by bucket+ W done by rope +W done by water)
the work done to lift the bucket = 1078 +474.32+1938.783 = 3491.103
the work done to lift the bucket = 3491 Joules
The density of a material is constant and it is given by the ratio of the mass to the volume of the material
The mass of the liquid and the full bottle ae
The mass of the liquid is <u>450 g</u>
The mass of the filled bottle is <u>530 grams</u>
<u></u>
The reason the above values are correct are as follows:
The given parameters are;
Volume of the bottle, V = Half litre
Mass of the bottle, = 80 g
The volume of liquid in the bottle when filled, V = 500 cm³
The density of the olive oil with which the bottle is filled, ρ = 0.9 g/cm³
a. Required:
To calculate the mass of oil in the bottle
Solution:
The volume of oil in the bottle when the bottle is filled, V = 500 cm³
The mass of the liquid, m = ρ × V
∴ m = 0.9 g/cm³ × 500 cm³ = 450 g
The mass of the liquid, m = <u>450 g</u>
<u></u>
b. The mass of the oil in the bottle, m = grams
The mass of the full bottle, = m +
∴ = 450 g + 80 g = 530 g
The mass of the full bottle, = <u>530 grams</u>
Learn more about density here: